-5y-9 =-(-1) A.- 1/2 B. -2 1/2 C. -2 D. -2/5
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Given the following table that gives data from a linear function:
![\begin {tabular} {|c|c|c|c|} Temperature, $y = f(x)$ (^\circ C)&0&5&20 \\ [1ex] Temperature, $x$ (^\circ F)&32&41&68 \\ \end {tabular}](https://tex.z-dn.net/?f=%5Cbegin%20%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%0ATemperature%2C%20%24y%20%3D%20f%28x%29%24%20%28%5E%5Ccirc%20C%29%260%265%2620%20%5C%5C%20%5B1ex%5D%0ATemperature%2C%20%24x%24%20%28%5E%5Ccirc%20F%29%2632%2641%2668%20%5C%5C%20%0A%5Cend%20%7Btabular%7D)
The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.
Recall that the equation of a straight line is given by
Using the points (32, 0) and (41, 5), we have:
The formular for the function can be obtained by choosing two points from the table and using the formular for the equation of a straight line.
Recall that the equation of a straight line is given by
Using the points (32, 0) and (41, 5), we have:
so since its just two factors, you can pick either for the "B" or "h", or one can say that the trinomial is the "B", because it can be factored into a couple more binomials, either way will work.