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Alenkinab [10]
3 years ago
14

For* 15-16 find the number of sides if a polygon has the given measure for each interior angle,

Mathematics
1 answer:
salantis [7]3 years ago
3 0

Answer:

15. d) 36

16. b) 20

17. d) 180

18. b) 50

19. c) 360

20. b) 60

Step-by-step explanation:

To find the number of sides a polygon has giving an interior angle, use the equation:

(number of sides - 2)*180/(number of sides) = measure of interior angle

<em>15. </em>(n = number of sides)

((n-2)*180)/n = 170

180n-360 = 170n

10n = 360

n = 36 (d)

<em>16.</em> (n = number of sides)

((n-2)*180)/n = 162

180n-360 = 162n

18n = 360

n = 20 (b)

<em>17.</em> The sum of the interior angles of a triangle is always 180 (d)

<em>18.</em> 180-60-70 = 50 (b)

<em>19.</em> The sum of the interior angles of a quadrilateral is always 360 (c)

<em>20.</em> 360-120-90-90 = 60 (b)

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4 0
3 years ago
Set up, but do not evaluate, the integral that represents the length of the curve given by x = 1 + 3t^2, y = 4 + 2t^3 over the i
kherson [118]

L

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∫

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f

t

i

√

(

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. Since  

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are perpendicular, it's not difficult to see why this computes the arclength.

It isn't very different from the arclength of a regular function:  

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a

√

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+

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d

y

d

x

)

2

d

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. If you need the derivation of the parametric formula, please ask it as a separate question.

We find the 2 derivatives:

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x

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t

=

3

−

3

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d

y

d

t

=

6

t

And we substitute these into the integral:

L

=

∫

√

3

0

√

(

3

−

3

t

2

)

2

+

(

6

t

)

2

d

t

And solve:

=

∫

√

3

0

√

9

−

18

t

2

+

9

t

4

+

36

t

2

d

t

=

∫

√

3

0

√

9

+

18

t

2

+

9

t

4

d

t

=

∫

√

3

0

√

(

3

+

3

t

2

)

2

d

t

=

∫

√

3

0

(

3

+

3

t

2

)

d

t

=

3

t

+

t

3

∣

∣

√

3

0

=

3

√

3

+

3

√

3

=6The arclength of a parametric curve can be found using the formula:  

L

=

∫

t

f

t

i

√

(

d

x

d

t

)

2

+

(

d

y

d

t

)

2

d

t

. Since  

x

and  

y

are perpendicular, it's not difficult to see why this computes the arclength.

It isn't very different from the arclength of a regular function:  

L

=

∫

b

a

√

1

+

(

d

y

d

x

)

2

d

x

. If you need the derivation of the parametric formula, please ask it as a separate question.

We find the 2 derivatives:

d

x

d

t

=

3

−

3

t

2

d

y

d

t

=

6

t

And we substitute these into the integral:

L

=

∫

√

3

0

√

(

3

−

3

t

2

)

2

+

(

6

t

)

2

d

t

And solve:

=

∫

√

3

0

√

9

−

18

t

2

+

9

t

4

+

36

t

2

d

t

=

∫

√

3

0

√

9

+

18

t

2

+

9

t

4

d

t

=

∫

√

3

0

√

(

3

+

3

t

2

)

2

d

t

=

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0

(

3

+

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t

2

)

d

t

=

3

t

+

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∣

∣

√

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0

=

3

√

3

+

3

√

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=

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√

3

Be aware that arclength usually has a difficult function to integrate. Most integrable functions look like the above where a binomial is squared and adding the two terms will flip the sign of the binomial.    

Be aware that arclength usually has a difficult function to integrate. Most integrable functions look like the above where a binomial is squared and adding the two terms will flip the sign of the binomial.

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Answer:

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