we have the number
![6-\sqrt[]{-40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B-40%7D)
Remember that
i^2=-1
so
substitute
![6-\sqrt[]{(i^2)40}](https://tex.z-dn.net/?f=6-%5Csqrt%5B%5D%7B%28i%5E2%2940%7D)
![6-2i\sqrt[]{10}](https://tex.z-dn.net/?f=6-2i%5Csqrt%5B%5D%7B10%7D)
therefore
the real part is 6
the imaginary part is -2√10
Answer:
George Washingmachine
Step-by-step explanation:
Hey mate!
You stuck?
^3 The cube root of 125=5
^2 The square root of 35=5.91
^3 The cube root of 64=4
^2 The square root of 38=6.16
Therefore your answer would be x2= 38, because 6.16 is greater than the other sums.
Hope this helps! :) (Don't forget Brainliest) :)
4x + 2 - 3x + 5 - 2(x + 5) = (2x - 5) + (3x + 4)
4x + 2 - 3x + 5 - 2x - 10 = 2x - 5 + 3x + 4
4x - 3x - 2x + 5 + 2 - 10 = 2x + 3x - 5 + 4
- x - 3 = 5x - 1
-x - 3 = 5x - 1 is the line above recopied
+x = +x
-3 = 6x - 1
<span> +1 = + 1 </span>
- 2 = 6x
- 2/6 = 6x/6
- 1/3 = x, the answer
