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eduard
3 years ago
9

A 146N force is needed to pull a 350 N block across a horizontal surface at a constant speed by a rope making an angle of 50 deg

rees with the floor. Find the coefficient of friction.
Physics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

F = force

f = friction

u = coefficient of friction

R = normal reaction force

a = Acceleration

m = mass of block

g = gravity

f = uR

F = Ma

Say the block is moving to the right.

The 146N force thus acts to the right, and the friction force to the left, since it resists movement.  

The 146N force acts to the right, but the horizontal component of it is 146 cos 50  = 93.84: So this is the force to the right.

Since F = uR and we're trying to find u, we need both F and R. R is easy to get since it is just m x g. This is in fact already given as the weight 350N. So R = 350.

The block is moving at a constant speed, so the force to the right must = the force to the left.

F = ma, so 93.84 - f = (350/g) x 0

This means f must be 93.84 also.  

so  we have f = uR,  

      93.84 = u x 350

so u = 0.268 or  

0.27 to 2dp.  

Hope you understand this.

Explanation:

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Glaciers, weather, and water shape Earth by _____.
Luden [163]
Glaciers, weather, and water shape Earth by (B.) the erosion.

Hope it helped you!

Have a great day!

-Charlie
6 0
3 years ago
Read 2 more answers
g If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of th
Reil [10]

Answer:

Speed; v = 17 m/s

Explanation:

We are given;

Radius; r = 110m

Angle; θ = 15°

Now, we know that in circular motion,

v² = rg•tanθ

Thus,

v = √(rg•tanθ)

Where,

v is velocity

r is radius

g is acceleration due to gravity

θ is the angle

Thus,

v = √(rg•tanθ) = √(110 x 9.8•tan15)

v = √(288.85)

v = 17 m/s

8 0
3 years ago
Compare and contrast angular momentum and linear momentum. How are mass and velocity related to momentum?
Cerrena [4.2K]

Answer:

Linear momentum is mass multiplied by velocity, so it follows that angular momentum is the moment of inertia, measured in kilogram meters squared, multiplied by angular velocity, measured in radians per second. Radians are just an alternative to degrees.

3 0
3 years ago
A child in a tree house uses a rope attached to a basket to lift a 24 N dog upward through a distance of 4.9 m into the house.
jenyasd209 [6]
<h3>Answer:</h3>

117.6 Joules

<h3>Explanation:</h3>

<u>We are given;</u>

  • Force of the dog is 24 N
  • Distance upward is 4.9 m

We are required to calculate the work done

  • Work done is the product of force and distance
  • That is; Work done = Force × distance
  • It is measured in Joules.

In this case;

Force applied is equivalent to the weight of the dog.

Work done = 24 N × 4.9 m

                  = 117.6 Joules

Hence, the work done in lifting the dog is 117.6 Joules

3 0
3 years ago
Consider a uniformly volume‑charged sphere of radius R and charge Q . What is the electric potential on the surface of the spher
VARVARA [1.3K]

To solve this problem we will start by applying the given load ratio, and we will rely on the two types of distances given. Later we will use Gauss's law and through its integrals, in which it is equivalent to the potential we will obtain its value in the center of the sphere. Since it is uniformly charged we have to,

\frac{Q'}{Q} = \frac{4\pi r^3}{4\pi R^3}

Q' = \frac{r^3}{R^3} Q

By Gauss Law

\phi = E \cdot 4\pi r^2

Here, E is the electric Field and is equal to

E = \frac{Q'}{\epsilon_0}

For \epsilon_0 being the Permeability constant at free space

Replacing with the previous value we have,

\phi = \frac{Qr^3}{\epsilon_0 R^3}

Then the value of the electric field is,

E = \frac{QR}{4\pi \epsilon_0 R^3}

Now potential

V = \int_0^R E\cdot dr'

V = - \frac{QR^2}{8\pi \epsilon_0 R^3}

V = -\frac{Q}{8 \pi \epsilon_0 R}

6 0
3 years ago
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