A. The time required for the ball to reach the wall is 0.26 s
B. The height of the ball when it hits the wall is 2.17 m
<h3>How to determine the speed of the ball in the horizontal direction</h3>
- Initial velocity (u) = 16 m/s
- Angle of projection (θ) = 37 degree
- Speed in the horizontal direction (uₓ) =?
uₓ = uCosθ
uₓ = 16 × Cos37
Speed in horizontal direction = 12.78 m/s
<h3>A. How to determine the time</h3>
- Speed in horizontal direction (uₓ) = 12.78 m/s
- Distance (s) = 3.3 m
- Time (t) =?
s = uₓ × t
3.3 = 12.78 × t
Divide both sides by 12.78
t = 3.3 / 12.78
t = 0.26 s
<h3>B. How to determine the height</h3>
- Acceleration due to gravity (g) = 9.8 m/s²
- Initial velocity (u) = 16 m/s
- Angle of projection (θ) = 37 degree
- Vertical velocity (vᵧ) = uSineθ = 16 × Sine 37 = 9.63 m/s
- Height (H) = ?
H = vᵧt - 1/2gt²
H = (9.63 × 0.26) - (1/2 × 9.8 × 0.26²)
H = 2.17 m
Learn more about projectile motion:
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