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jolli1 [7]
2 years ago
8

in a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall with a speed of 16 m/s

at an angle of 37 degree above the horizontal. (a) What amount of time is required for the ball to reach the wall if it is 3.3m away? (b) How high is the ball when it hits the wall?
Physics
1 answer:
vladimir1956 [14]2 years ago
7 0

A. The time required for the ball to reach the wall is 0.26 s

B. The height of the ball when it hits the wall is 2.17 m

<h3>How to determine the speed of the ball in the horizontal direction</h3>
  • Initial velocity (u) = 16 m/s
  • Angle of projection (θ) = 37 degree
  • Speed in the horizontal direction (uₓ) =?

uₓ = uCosθ

uₓ = 16 × Cos37

Speed in horizontal direction = 12.78 m/s

<h3>A. How to determine the time</h3>
  • Speed in horizontal direction (uₓ) = 12.78 m/s
  • Distance (s) = 3.3 m
  • Time (t) =?

s = uₓ × t

3.3 = 12.78 × t

Divide both sides by 12.78

t = 3.3 / 12.78

t = 0.26 s

<h3>B. How to determine the height</h3>
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Initial velocity (u) = 16 m/s
  • Angle of projection (θ) = 37 degree
  • Vertical velocity (vᵧ) = uSineθ = 16 × Sine 37 = 9.63 m/s
  • Height (H) = ?

H = vᵧt - 1/2gt²

H = (9.63 × 0.26) - (1/2 × 9.8 × 0.26²)

H = 2.17 m

Learn more about projectile motion:

brainly.com/question/20326485

#SPJ1

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