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Dmitry_Shevchenko [17]
3 years ago
13

A wagon with an initial velocity of 2 m/s and a mass of 60 kg, gets a push with 150 joules of

Physics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

v_f = 3 m/s

Explanation:

From work energy theorem;

W = K_f - K_i

Where;

K_f is final kinetic energy

K_i is initial kinetic energy

W is work done

K_f = ½mv_f²

K_i = ½mv_i²

Where v_f and v_i are final and initial velocities respectively

Thus;

W = ½mv_f² - ½mv_i²

We are given;

W = 150 J

m = 60 kg

v_i = 2 m/s

Thus;

150 = ½×60(v_f² - 2²)

150 = 30(v_f² - 4)

(v_f² - 4) = 150/30

(v_f² - 4) = 5

v_f² = 5 + 4

v_f² = 9

v_f = √9

v_f = 3 m/s

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patriot [66]

According to the pavlovian perspective, people who suffer from PTSD are classically conditioned.

<h3>What is PSTD?</h3>

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The pavlovian perspective however view this disorder as being a type of classical conditioned one.

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5 0
2 years ago
A cylindrical rod 21.5 cm long with a mass of 1.20 kg and a radius of 1.50 cm has a ball of diameter of 6.90 cm and a mass of 2.
Sergeeva-Olga [200]

Answer

given,

length of rod = 21.5 cm = 0.215 m

mass of rod (m) = 1.2 Kg

radius, r  = 1.50

mass of ball, M = 2 Kg

radius of ball, r = 6.90/2 = 3.45 cm = 0.0345 m

considering the rod is thin

I = \dfrac{1}{3}M_{rod}L^2 + [\dfrac{2}{5}M_{ball}R^2+M_{ball}(R+L)^2]

I = \dfrac{1}{3}\times 1.2 \times 0.215^2 + [\dfrac{2}{5}\times 2 \times 0.0345^2+2\times (0.0345 +0.215)^2]

     I = 0.144 kg.m²

rotational kinetic energy of the rod is equal to

KE = M_{rod}g\dfrac{L}{2} + M_{ball}g(L+R)^2

KE = 1.2 \times 9.8 \times \dfrac{0.215}{2} + 2\times 9.8\times (0.215+0.0345)^2

  KE = 6.15 J

b) using conservation of energy

   K_f + U_f = K_i + U_i + \Delta E

   \dfrac{1}{2}I\omega^2+ 0=0 + 6.15+0

   \dfrac{1}{2}\times 0.144 \times \omega^2= 6.15

    ω = 9.25 rad/s

c) linear speed of the ball

     v  =  r ω

     v  =  (L+R )ω

     v  =  (0.215+0.0345) x 9.25

     v =2.31 m/s

d) using equation of motion

  v² = u² + 2 g h

  v² = 0 + 2 x 9.8 x 0.248

   v = √4.86

  v =2.20 m/s

speed attained by the swing is more than free fall

  % greater = \dfrac{2.31-2.20}{2.20}\times 100

                   = 5 %

speed of swing is 5 % more than free fall

6 0
3 years ago
What local constellation signifies the start of rainy season in the Philippines?
igor_vitrenko [27]

Answer:

Buwaya

Explanation:

Constellations are the patterns imagined by joining stars together. Ancient people used to imagine these patterns and further related the appearance of constellations with natural phenomenon. Similarly constellations can also be related with a particular season depending upon the visibility. For example, Orion signifies the start of the winters in Northern hemisphere.

The rainy season in Philippines starts in the month of June the same time  when Buwaya (local name given to the box in Pegasus constellation) starts being seen in the sky after a brief period of disappearance from the sky.

7 0
3 years ago
Read 2 more answers
What must you know in order to determine the gravitational force between two objects?
Ganezh [65]
You must know the masses of both objects and the gravitational constant used to calculate the gravitational force between the 2 objects.
5 0
3 years ago
A +15 nC point charge is placed on the x axis at x = 1.5 m, and a -20 nC charge is placed on the y axis at y = -2.0m. What is th
IceJOKER [234]

Answer:E=75\ N/m

Explanation:

Given

First charge of q_1=15\ nC is placed at x=1.5\ m

Second charge  q_2=-20\ nC is placed at y=-2\ m

Electric field is given by

E=\frac{kq}{r^2}

Electric field due to q_1 is away from it

E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}

E_1=60\ N/m

Electric field due to q_2

E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}

E_2=45\ N/m

Net electric field will be vector addition of two

\vec{E_{net}}=\vec{E_1}+\vec{E_2}

\vec{E_{net}}=-60\hat{i}-45\hat{j}

Magnitude of Electric field is

E=\sqrt{60^2+45^2}

E=75\ N/m

8 0
3 years ago
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