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liberstina [14]
3 years ago
10

Calculate 95% of $1,350.

Mathematics
2 answers:
sineoko [7]3 years ago
5 0
95% of $1350 is: 1282.5
Keith_Richards [23]3 years ago
4 0

Answer:

1282.5

Step-by-step explanation:

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Lucy made $65 for 5 hours of work.
shusha [124]

Answer:

169

Step-by-step explanation:

65 divided by 5 to get 13

and multiply that with 13

like this: 13x13

to get 169

6 0
3 years ago
Read 2 more answers
What is the solution for the following system of equations?Use ANY method to solve.
mezya [45]
Its c.
If you will substitute those numbers to the pair of equations, both will be true.

1=-3+4
1=3-2
8 0
3 years ago
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A state has a limit on the lengths of cargo trains. The train cannot exceed a length of 1,100 ft. Train A has 28 cars at 40 feet
Bezzdna [24]
Hey there!

For this problem, all you need to do is some multiplication:

40 ft per car * 28 cars = 1,120 ft total
30 ft per car * 34 cars = 1,020 ft total

You can see that Train A exceeds the limit, while Train B doesn't.

Hope this helped you out! :-)
6 0
3 years ago
Sketch the following to help answer the question. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals
BigorU [14]

Kite has two pairs of adjacant sides equal. So side QR is either equal to QT or to RS. If side QR equals QT. So then QT = 17

Diagonals in kite cross each other at right angle. So in right trinagle QPT, QT is hypotenuse. Now if QT = 17, and we are given PT = 25. We cannot have hypotenuse smaller than other side. So QR cannot be equal to side QT. So QR has to be equal to other adjacent side RS. So we will have kite QRST as shown in figure.

So RS = 17. If side QR and RS are equal so diagonal RT will bisect(divide in half) diagonal QS then.

AS QS = 30 (given) so PS = PQ = \frac{30}{2} = 15

Now in right triangle RPS we have

RS = 17

PS = 15

We have to find other side RP.

For that we will use pythagorean formula

c^{2} = a^{2} + b^{2} where c is the hypotenuse side and a and b are the other two sides of triangle

So in right triangle RPS we will have hypotenuse as RS (opposite ot right angle) so we will have

RS^{2} = PS^{2} + RP^{2}

Now plug values in equation. Plug 17 in RS place, 15 in PS place and RP is known so let that be x

17^{2} =  x^{2} + 15^{2}

289 = x^{2} + 225

now solve for x as shown

289 - 225 = x^{2} + 225 - 225

64 = x^{2}

\sqrt{64} = \sqrt{x^2}

8 = x

So RP = 8

Also we are given PT = 25

So diagonal RT= RP + PT = 8 + 25 = 33m

Area of kite is given by formula

\frac{pq}{2} where p and q are the diagonals in kite

Here we have digonal RT= 33m and diagonal QS = 30m

So area = \frac{33 \times 30}{2} = \frac{990}{2} =495 m^{2}

so final answer for area of kite is 495 m^{2}

4 0
3 years ago
Let a be the sum of the last four digits and let b be the last digit of your 8-digit student id. (example: for 20245347, a = 19
pav-90 [236]

Using the student id given above, a = 19 and b = 7

Average speed for the first 54 km = 48+a km/h

Plug a = 19

Average speed for the first 54 km = 48+19 = 67 km/h

Average speed for remaining 86 km = 43-b km/h where b = 7

Average speed = 36 km/h

Average speed of entire journey = total distance / total time taken

speed = \frac{distance}{time}  and  time = \frac{distance}{speed}

Time taken to cover 54 km = \frac{54}{67} hr

Time take to cover 86 km = \frac{86}{36} hr

Total time taken = 3.2 hours.

Total distance = 86+54= 140 km

Average speed of the entire trip = \frac{140}{3.2} = 43.75 km/ h

6 0
4 years ago
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