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Zanzabum
2 years ago
13

Help please I need help

Mathematics
1 answer:
lukranit [14]2 years ago
8 0
The answer is Radical 6.

This is because if you use Cosine and the angle measured 30. You would put adjacent over hypotenuse, which is
Cos (30) = X/radical 8

Put this into your calculator to get Radical 6
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ANSWERS: <br> •$5,948.49<br><br> •$8,922.72<br><br> •$14,871.21<br><br> •$29,742.41
boyakko [2]

Answer: c) 14,871

Step-by-step explanation:

See photo attached - if my work doesn’t make sense I can explain it, just ask (:

8 0
3 years ago
Which of the following is defined by a line divides two sides of a triangle
photoshop1234 [79]

Answer: A

Step-by-step explanation:

Triangle Proportionality Theorem Converse states that if a line divides two sides of a triangle proportionally, then it is parallel to the third side.

4 0
3 years ago
Verizon has a special and is selling the new IPhone 7 for $299 to new customers. If the Apple Store is charging twice as much as
photoshop1234 [79]

Answer:

the answer is $598

Step-by-step explanation:

299×2=598

4 0
3 years ago
SOMEONE ANWSER QUICK !
xenn [34]

Answer:

I think that the answer would be C because you have to multiply the term at the top. This would mean you would not do C. Sorry if this is wrong. At least you have your eliminating process now. lol so doing C is out of the box, which makes C your answer.

Step-by-step explanation:

6 0
3 years ago
30 POINTS AVAILABLE
kherson [118]

Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

3 0
3 years ago
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