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Vinvika [58]
3 years ago
6

The first jar has a liquid and room temperature. It is colorless. It has a density of of approximately.8. What is it? O Water O

Ice Ethanol O Oxygen​
Chemistry
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

water

Explanation:

I'm not sure though

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A mixture of CO2 and Kr weighs 35.0 g and exerts a pressure of 0.708 atm in its container. Since Kr is expensive, you wish to re
ollegr [7]

Explanation:

Since, it is given that carbon dioxide is completely removed by absorption with NaOH. And, pressure inside the container is 0.250 atm.

For Kr = 0.250 atm and pressure CO_{2} will be calculated as follows.

           CO_{2} = (0.708 - 0.250) atm

                       = 0.458 atm

Now, we will calculate the mole fraction as follows.

            CO_{2} = \frac{0.458}{0.708}

                       = 0.646

               Kr = \frac{0.250}{0.708}

                    = 0.353

Now, we will convert into gram fraction as follows.

              CO_{2} = 0.646 \times 44

                          = 28.424

                   Kr = 0.353 \times 83.78

                        = 29.57

Therefore, total mass is calculated as follows.

           Total mass = (28.424 + 29.57)

                              = 57.994

Hence, the percentage of CO_{2} and Kr are calculated as follows.

          CO_{2} = \frac{28.424}{57.99} \times 100

                     = 49%

               Kr = \frac{29.57}{57.99} \times 100

                    = 51%

Hence, amount of CO_{2} and Kr present i mixture is as follows.  

         CO_{2} in mixture = 35 \times 0.49

                             = 17.15 g

                  Kr = 35 \times 0.51

                       = 17.85 g

Thus, we can conclude that 17.15 g of CO_{2} is originally present and 17.85 g of Kr is recovered.

6 0
3 years ago
Calculate the ph of the solution resulting from the addition of 85.0 ml of 0.35 m hcl to 30.0 ml of 0.40 m aniline (c6h5nh2). kb
stiv31 [10]

Answer:

pH = 0.81

Explanation:

HCl reacts with aniline, thus:

C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻

Moles of HCl are:

0.085L × (0.35mol HCl / L) = <em>0.02975mol HCl</em>

Moles of aniline are:

0.030L × (0.40mol HCl / L) = <em>0.012mol aniline</em>

Thus, after reaction, will remain:

0.02975mol - 0.012mol = <em>0.01775mol HCl</em>

Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: <em>0.01775mol H⁺</em>

As total volume is 85.0mL + 30.0mL = 115.0mL ≡ <em>0.115L</em>

0.01775mol / 0.115L = 0.1543M

pH of solution = -log[H⁺]

pH = -log 0.1543M

<em>pH = 0.81</em>

<em></em>

3 0
3 years ago
Read 2 more answers
Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 × 10-17.
Alex787 [66]
When the salt AgI dissolves in water it dissociates as follows;
AgI ---> Ag⁺ + I⁻
molar solubility is the number of moles that are dissolved in 1 L of solution.
If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.
the formula for solubility product constant - ksp of AgI is given below 
ksp = [Ag⁺][I⁻]
ksp = (x)(x)
ksp = 8.51 x 10⁻¹⁷ 
therefore,
x² = 8.51 x 10⁻¹⁷
x = 9.22 x 10⁻⁹
since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M
3 0
3 years ago
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Instead of using CAT-scans and X-rays to see the center of the Earth, researchers use waves emitted by earthquakes to get a sense of the planet's innards. Just like an X-ray, seismic waves bounce around, changing direction and speed based on the material they pass through.

7 0
3 years ago
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In the "heavy
Bond [772]

Heavy water contains 20% hydrogen by mass and 80% oxygen by mass.

<h3>What is the molar mass of heavy water?</h3>

Heavy water is water which contains the heavy isotope of hydrogen, Hydrogen-2 in its molecules.

The mass of heavy water is greater than that of water.

The molar mass of heavy water is 20.0 g

The percentage composition of the elements in heavy water are as follows:

Hydrogen = 2 × 2g/20 g ×100% = 20%

Oxygen = 16g/20g × 100% = 80%.

Therefore, Heavy water contains 20% hydrogen by mass and 80% oxygen by mass.

Learn more about heavy water at: brainly.com/question/2142633

#SPJ1

3 0
2 years ago
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