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2 years ago

Calculate the amount of solvent needed to prepare 50g of 10% solution of Tincture iodine. Name the solvent.

Chemistry

1 answer:

sergeinik [125]2 years ago

7 0

Answer:

Calculate the amount of solvent needed to prepare 50g of 10% solution of tincture Iodine.

Name the solvent

Explanation:

sodium

Hope it is helpful.....

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A sample of Hydrogen gas has a volume of 25.5 liters at a pressure of 15.0 kPa. If the temperature is kept constant and the pres

patriot [66]

Answer:

<h2>7.65 litres </h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

15 kPa = 15,000 Pa

50 kPa = 50,000 Pa

We have

$V_2 = \frac{15000 \times 25.5}{50000} = \frac{382500}{50000} \\ = 7.65$

We have the final answer as

<h3>7.65 litres </h3>

Hope this helps you

5 0

2 years ago

Which is the force of attraction that holds atoms together?

Morgarella [4.7K]

B) chemical bond i believe is the correct answer

3 0

3 years ago

An unknown solution has a pH of 7. How would you classify this solution?

xenn [34]

Solution with a ph of 7 Is neutral

7 0

2 years ago

The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?

anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

$K_a\times K_b=K_w$

$K_b$ for sodium formate is $K_b=\frac {K_w}{K_a}$

Given that:

$K_a$ of formic acid = $1.8\times 10^{-4}$

And, $K_w=10^{-14}$

So,

$K_b=\frac {10^{-14}}{1.8\times 10^{-4}}$

$K_b=5.5556\times 10^{-11}$

Concentration = 0.35 M

HCOONa ⇒ Na⁺ + HCOO⁻

Consider the ICE take for the formate ion as:

HCOO⁻ + H₂O ⇄ HCOOH + OH⁻

At t=0 0.35 - -

At t =equilibrium (0.35-x) x x

The expression for dissociation constant of sodium formate is:

$K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}$

$5.5556\times 10^{-11}=\frac {x^2}{0.35-x}$

Solving for x, we get:

x = 0.44×10⁻⁵ M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

5 0

2 years ago

What indicators of a chemical reaction occurred in the following equation?

ch4aika [34]

Answer:

1) evolution of gas

2) evolution of heat

Explanation:

In this reaction, glucose is broken down into its constituents; carbon dioxide and water. The question is to decipher indicators of a chemical reaction from the equation.

If we look at the equation carefully, we will notice that a gas was evolved (CO2). The evolution of a gas indicates that a chemical reaction must have taken place. Secondly, energy is given off as heat. This is another indication that a chemical reaction has taken place.

6 0

2 years ago