Answer:
Van't Hoff factor for AlCl₃ = 3 (Approx)
Explanation:
Given:
Number of observed particular = 1.79 M
Number of theoretical particular = 0.56 M
Find:
Van't Hoff factor for AlCl₃
Computation:
Van't Hoff factor for AlCl₃ = Number of observed particular / Number of theoretical particular
Van't Hoff factor for AlCl₃ = 1.79 M / 0.56 M
Van't Hoff factor for AlCl₃ = 3.19
Van't Hoff factor for AlCl₃ = 3 (Approx)
The correct answer is q < 0. Hope this helps you!!
Answer:
Hydrogen
Explanation:
This may be wrong but I can't really tell because of how you have written the question
The activation energy in the
diagram is 43.8 kcal/ mole, letter C. You have to note that activation energy
is the energy needed for the reaction to occur and produce products. Therefore,
the spike after H2 and I2 is reacted is the activation energy of the reaction.
