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3 years ago

What is filtration? ㅜㅜ ㅜㅜ

Chemistry

1 answer:

Aleks04 [339]3 years ago

4 0

Answer:

filtration is the process of using a filter to remove solids from liquids or gasses.

Example:

an example of this is tea.

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List 3 physical properties of copper?

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It is a soft,malleable,and ductile metal

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3 years ago

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tia_tia [17]

Answer:

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Explanation:

DON'T USE DRUGS BECAUSE IT IS GOING DEATH

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3 years ago

What happens when gases change to plasma?

IgorLugansk [536]

Answer:. In the case of neon, it is electrical energy that pulls the electrons off.

explanation-Plasma can be made from a gas if a lot of energy is pushed into the gas. In the case of neon, it is electrical energy that pulls the electrons off. When it is time to become a gas again, just flip the neon light switch off. Without the electricity to energize the atoms, the neon plasma returns to its gaseous state.

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3 years ago

if the side if a chemical equation has 3, carbon atoms, 6 oxygen atoms and 4 hydrogen atoms then the right side of the chemical

DochEvi [55]

The right side will also have 3 carbon, 6 oxygen, and 4 hydrogen atoms. the atoms may come together to form a compound but it doesn't lose any atoms. Hope it helped!

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3 years ago

In each case, calculate the appropriate ratio to show that the information given is consistent with the law of multiple proporti

Alchen [17]

Answer:

(a) 3:2; (b) 2:1

Explanation:

The Law of Multiple Proportions states that when two elements A and B combine to form two or more compounds, the masses of B that combine with a given mass of A are in the ratios of small whole numbers.

That is, if one compound has a ratio r₁ and the other has a ratio r₂, the ratio of the ratios r is in small whole numbers.

(a) Ammonia and hydrazine.

In ammonia, the mass ratio of H:N is r₁ = 0.2158/1

In hydrazine, the mass ratio of H:N is r₂ = 0.1439/1

The ratio of the ratios is:

$r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 0.2158}{0.1439} = \dfrac{1.500 }{1} = \dfrac{2.999}{2} \approx \mathbf{\dfrac{3}{2}}\\\\\text{The relative amounts of H in the two compounds are in the ratio }\boxed{\mathbf{\dfrac{3}{2}}}$

(b) Nitrogen oxides

In nitrogen monoxide, the mass ratio of O:N is r₁ = 1.142/1

In dinitrogen monoxide, the mass ratio of O:N is r₂ = 0.571/1

The ratio of the ratios is:

$r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 1.142}{0.571} = \dfrac{2.000 }{1} \approx \mathbf{\dfrac{2}{1}}\\\\\text{The relative amounts of O in the two compounds are in the ratio }\boxed{\mathbf{\dfrac{2}{1}}}$

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3 years ago