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3 years ago

You have 2 moles of NaOH how many molecules of NaOH?

Chemistry

1 answer:

kaheart [24]3 years ago

4 0

Answer:

12.044 X 10^23 molecules of NaOH

Explanation:

because NaOH is an ionic bond, we should be asking how many <em>formula units </em> are in 2 moles of NaOH, there are 0 molecules since NaOH is measured in formula units.

but for the sake of the problem I'll assume NaOH is measured in molecules

for every mol of something there are 6.022 X 10^23 of something of that something.

so there are 6.022 X 10^23 molecules for every mol of NaOH

that means we have 2 X 6.022 X 10^23 molecules in 2 moles of NaOH = 12.044 X 10^23 molecules of NaOH

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Which term describes this reaction?

DedPeter [7]

Answer:

Explanation:

This is a reaction of elimination, because the water was removed and because of it double bond is formed.

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3 years ago

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

sveta [45]

Explanation:

The given data is as follows.

$E^{o}$ = 0.483, $[Co^{3+}]$ = 0.173 M,

$[Co^{2+}]$ = 0.433 M, $[Cl^{-}]$ = 0.306 M,

$P_{Cl_{2}}$ = 9.0 atm

According to the ideal gas equation, PV = nRT

or, P = $\frac{n}{V}RT$

Also, we know that

Density = $\frac{mass}{volume}$

So, P = MRT

and, M = $\frac{P}{RT}$

= $\frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}$

= $\frac{9.0}{24.436}$

= 0.368 mol/L

Now, we will calculate the cell potential as follows.

E = $E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}$

= $0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}$

= $0.483 - 0.02955 log \frac{0.0689}{0.0162}$

= $0.483 - 0.02955 \times 0.628$

= 0.483 - 0.0185

= 0.4645 V

Thus, we can conclude that the cell potential of given cell at $25^{o}C$ is 0.4645 V.

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4 years ago

Which pair of elements have the same valence electronic configuration of np³?

Dennis_Churaev [7]

Answer:

Explanation:

We can determine the number of valence electrons of an element:

If it belongs to Groups 1 and 2, the number of valence electrons is equal to the number of group and the differential electron occupies the s subshell.

If it belongs to the groups 13-18, the number of valence electrons is equal to: "Number of group - 10" and the differential electron occupies the p subshell.

Which pair of elements have the same valence electronic configuration of np³?

(a) O and Se. NO. They belong to the group 16 and the valence electron configuration is ns² np⁴.

(b) Ge and Pb. NO. They belong to the group 14 and the valence electron configuration is ns² np².

(d) K and Mg. NO. They belong to the groups 1 and 2 and the valence electron configuration is ns¹ and ns².

(e) Al and Ga. NO. They belong to the group 13 and the valence electron configuration is ns² np¹.

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3 years ago

Select all the correct answers.

stich3 [128]

Answer : The products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

Explanation :

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The acid-base reaction will be:

$HClO_3+LiOH\rightarrow LiClO_3+H_2O$

Therefore, the products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

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Mrac [35]

A specific mass of a gas has a fixed volume at room temperature

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3 years ago