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anyanavicka [17]
3 years ago
14

What is the voline of the figure below?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

it's 353.77

Step-by-step explanation:

V=πr2h

3=π·6.52·8

3≈353.95277

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A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro
Mrac [35]

Answer:

The equation of the displacement d as a function of time t is :

d(t)=8sin(\pi t+\pi )

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple sin or cos terms.

Thus,

d(t) = Asin(wt+c)

is the general form of displacement of a SHM.

where,

  • <em>d(t) is the displacement with respect to the mean position at any time t</em>
  • <em>A is amplitude </em>
  • <em>w is the natural frequency of oscillation (rads^{-1})</em>
  • <em>c is the phase angle which indicates the initial position of the object in SHM (rad)</em>

given,

  1. Time period (T) = 2s
  2. A=8
  3. The natural frequency (w) and time period (T) is :

                               w=\frac{2\pi} {T}

∴

w = \frac{2\pi }{2}  = \pi rads^{-1}

∴

the equation :

<em>⇒d(t)=8sin(\pi t+c)    </em>                    ------1

since d=0 when t=o ,

<em>⇒0=8sinc\\c=n\pi                         ------2</em>

where n is an integer ;

<u>⇒since the bouy immediately moves in the negative direction , x must be negative or c must be an odd multiple of \pi.</u>

<em>⇒ d(t) = 8sin(\pi t+(2k+1)\pi )         ------3</em>

where k is also an integer ;

the least value of k=0;

thus ,

the equation is :

d(t)=8sin(\pi t+\pi )

<em></em>

7 0
3 years ago
Is the following relation a function? (1 point)
Margarita [4]

If there are no repeating x values and an x value only goes to <em>one</em><em> </em>y value, then yes, it is a function.

3 0
3 years ago
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What is 2x6+14+15+27-2
Andrews [41]
Use a calculator kkkkk
5 0
3 years ago
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Estimate each product.solve to check your estimate.40×6
Fed [463]
Well 40 times 6 is 240 which means that you don't have to round.
8 0
3 years ago
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Find the midpoint of the line segment JK if j (4,6) and k(0,-4)
Snowcat [4.5K]

Answer:

(2,1)

General Formulas and Concepts:

Order of Operations: BPEMDAS

Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define points</u>

J (4, 6)

K (0, -4)

<u>Step 2: Find midpoint</u>

  1. Substitute:                         (\frac{4+0}{2},\frac{6-4}{2})
  2. Add/Subtract:                    (\frac{4}{2},\frac{2}{2})
  3. Divide:                               (2,1)
4 0
3 years ago
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