1st digit cannot be 0 so there are 9 choices {1,2,3,4,5,6,7,8,9}. The middle 4 digits have 10 choices (can have 0). The last digit must be EVEN or 0 to make the entire 6 digit number even, {0,2,4,6,8} = 5 choices
9×10×10×10×10×5 = 450,000
Answer:
Value of x is 2
Step-by-step explanation:
Given
BD = 6
DA = 4
BE = 
EC = x
Also segment DE is parallel to segment AC
∴ By using Midpoint theorem which states
Putting the given data in above equation we get
Answer:
7/15
Step-by-step explanation:
7 boxes out of 10 contain $20. Therefore 3 boxes do not have $20 bills.
The probability of picking a bag with a $20 bill
= 7/10
The probability of picking another bag with $20 bill
= (7-1)/(10-1)
= 6/9
The probability of getting two $20 bills.
= 7/10 × 6/9
= 42/90
= 7/15
Answer:
the 1st option is false; there is no 'addition' sign
Step-by-step explanation:
Answer:why
Step-by-step explanation:
because i don't know
