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2 years ago

What is the value of 11−3m , when m = 2? (Please do it step by step because I dont know how to do this ;[ )

1 answer:

6 0

Substitute the variable for the value given.

11 - 3m becomes 11 - 3(2)

Now do the order of operations.

11 - 3(2) =
11 - 6 =
5

So, the answer is 5.

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-5x=10 plz no links thanks

Yakvenalex [24]

Answer:

Step-by-step explanation:

2x5=10

6 0

2 years ago

Read 2 more answers

¿cual es el perimetro total de un paralelogramo obicuo cuya base mide 2∛54x² cm , y cuyo lado oblicuo mide 3∛54x²?

Step2247 [10]

Answer:

$p=10\sqrt[3]{54}x^2$

Step-by-step explanation:

We are given parallelogram

Since, two opposite sides of any parallelogram are always equal

Let's assume first side =a

second side =b

so, we get

$a=2\sqrt[3]{54}x^2$

$b=3\sqrt[3]{54}x^2$

now, we can find perimeter

perimeter=2a+2b

so, we get

$p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)$

we can simplify it

$p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2$

$p=10\sqrt[3]{54}x^2$ ................Answer

6 0

2 years ago

Read 2 more answers

I don’t understand this, need help.

zaharov [31]

Answer:

8 units

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always

NeTakaya

Answers:

A) $-\frac{11}{4}$

C) $m_{1}=\frac{Fr^{2}}{G m_{2}}$

Step-by-step explanation:

Part 1:

We have the followig equation:

$\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}$

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

$\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}$

Solving for the left part of the equation:

$\frac{2x-17}{15}=\frac{4x-1}{8}$

Operating with cross product:

$8(2x-17)=15(4x-1)$

Applying the distributive property:

$16x-136=60x-15$

Isolating $x$ :

$x=-\frac{121}{44}$

Dividing numerator and denominator by 11:

$x=-\frac{11}{4}$ Hence, the correct option is A

Part 2:

We have the followig equation:

$F=\frac{G m_{1} m_{2}}{r^{2}}$

Operating with cross product:

$Fr^{2}=G m_{1} m_{2}$

Isolating $m_{1}$ :

$m_{1}=\frac{Fr^{2}}{G m_{2}}$ Hence, the correct option is C

5 0

3 years ago

write an expression containing x-terms and constants. The x-terms schould combine to 7x and the constants should sum to 13

S_A_V [24]

2x+12+6x+1-x You are adding up 2x and 6x and deduct 1x so you get 7x You add up 12 and 1 which gives 13

6 0

2 years ago