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alisha [4.7K]
2 years ago
12

Please help meeeeeeeee

Mathematics
1 answer:
Anna11 [10]2 years ago
6 0

Answer:

Ues math w/a/y

Step-by-step explanation:

ues it

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4m^2-3mn^2+5

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Simplify the expression (show ur work)
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Step-by-step explanation:

\sqrt[3]{125y^9z^6}\\ \\ \sqrt[3]{5^3(y^3)^3(z^2)^3}\\ \\ 5y^3z^2

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Variable definition?
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The number beside the letter . for example 6x, 6 would be the variable
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3 years ago
[IMPORTANT PLEASE READ!!] I am currently at home, I'm in summer school for Algebra 1. I'm taking a pre-test, once I finish this
Llana [10]
<h2>Answer:</h2>

The vertex of the function is:

                             (-2,-2)

<h2>Step-by-step explanation:</h2>

We are given a absolute value function f(x) in terms of variable "x" as:

                       f(x)=-|x+2|-2

We know that for any absolute function of the general form:

f(x)=a|x-h|+k

the vertex of the function is : (h,k)

and if a<0 the graph of function opens downwards.

and if a>0 the graph of the function opens upwards.

Hence, here after comparing  the equation with general form of the equation we see that:

a= -1<0 , h= -2 and k= -2

Since a is negative , hence, the graph opens down .

         Hence, the vertex of the function is:

                         (-2,-2)

3 0
2 years ago
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Could someone do all the problems and/or check my work?
MArishka [77]
11. You’ve done it correctly

12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2

13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution

14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath

15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4

Hope this helped :)
8 0
3 years ago
Read 2 more answers
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