All categories

2 years ago

BE is a diameter of the circle, ABC is a tangent to the circle. Find the size of angle ABD. Find the size of angle DEB

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

5 0

Answer: both 66

Step-by-step explanation:

A) 66

B) 66

You might be interested in

If u can answer this i will give u branliest but there is no way u can

Stolb23 [73]

n is even

hehehehe :3

4 0

2 years ago

What are the domain and range of the function f(x) = 3x + 5

fredd [130]

Step-by-step explanation:

Here,let x = 1,2,3 and 4

Then,

Domain =(1,2,3,4)

Again,

f(1)= 3*1 + 5

=3 + 5

f(2)=3*2 + 5

=6 + 5

=11

f(3)=3*3 + 5

=9 + 5

=14

f(4)=3*4 + 5

=12 + 5

=17

Therefore, Range=(8,11,14,17)

7 0

1 year ago

Re write the equation in standard form y=8x+2

quester [9]

Standard form: 8x - y = -2

5 0

2 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

The first one: $(\frac{1}{2})^{n-1}$ is a geometric sequence of first term ( $a_1$ ) "1" and common ratio (r) " $\frac{1}{2}$ ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: $Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2$

The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum: