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3 years ago

BE is a diameter of the circle, ABC is a tangent to the circle. Find the size of angle ABD. Find the size of angle DEB

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer: both 66

Step-by-step explanation:

A) 66

B) 66

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What is the slope between the points<br> (-6,1) and (4,-4) ?

alex41 [277]

Answer:

gfdfcffhhddfnjg gfdfcffhhddfnjg rrrfffffffffgfffffffffffgggggfffcccfcffdfdf

hgggggvvghggggggggt hgggggvvghggggggggt

ggggggggg

Step-by-step explanation:

ttttttttttttttttttttrrtttttttttttrtttttttttttggtttttrrttrrttttrrrrtttttrrrrrrrrtttttttttttttttttt

6 0

3 years ago

All functions have a domain and a range.<br> True<br> False

Elza [17]

Answer:

True

Step-by-step explanation:

The definition of the function is a relation with exactly one x for each y. x is the domain, and y is the range, so all functions have a domain and a range.

6 0

3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago

What is the formula for the following geometric sequence? -5, -10, -20, -40, ... an = -5 · 2n - 1 an = -5 · (-2)n - 1 an = -2 ·

vazorg [7]

$-5 * 2^{n-1}$

8 0

3 years ago

Erik pays $225 in advance on his account at the athletic club. Each time he uses the club, $9 is deducted from the account. Writ

guajiro [1.7K]

Answer:

Step-by-step explanation:

225-9x=v

225-9(7)=v

225-63=v

162=v

your answer is A

4 0

3 years ago