BE is a diameter of the circle, ABC is a tangent to the circle. Find the size of angle ABD. Find the size of angle DEB

Try one last time

Ierofanga [76]

Answer:

$144

Step-by-step explanation:

divide 272 by 17 and then multiply that answer by 9

272/17 is 16

so 16 dollars an hour

multiply that by 9

you get 144

3 0

3 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago

6

pshichka [43]

Answer:

47.4%

Step-by-step explanation:

It has to be below 50% because those weights fall at or below the average.

8 0

3 years ago

Write an expression the represents the statement "Add 9 and 3, then multiply by 6"

ELEN [110]

Answer:

6(9+3)

Explanation:

Add 9 and 3 which is 9 + 3

THEN multiply by 6 which is 6(9 + 3)

I put parentheses because it's sayings to add first and then multiply!

3 0

2 years ago

There is a group of 10 people who are ordering pizza. If each person gets 2 slices and each pizza has 4 slices, how many pizzas

Sonbull [250]

Answer:

5 pizzas

Step-by-step explanation: If you have 10 people and each will get two slices then you will need 20 pieces of pizza because 10x2 is 20. If each pizza has 4 slices then you will need 5 pizzas because 4/20 is 5.

6 0

2 years ago

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