Answer:
Step-by-step explanation:
We can answer this in two ways: Differentiation and Graphing.
<u>Differentitate:</u>
The first derivative of a function yields a function that provides the slope for any point on the line of the original function. The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.
f(x) = 3(x-1)^2 + 4
f(x) = 3(x-1)(x-1) + 4
f(x) = 3(x^2 - 2x + 1) + 4
f(x) = 3x^2 - 6x + 7
f'(x) = 6x -6
Set this = 0 and find x:
0 = 6x -6
x = 1
The value of y when x=1 in the original equation is:
f(1) = 3(1-1)^2 + 4
y = 4
The vertex is (1,4)
<u>Graph:</u>
You can use DESMOS to plot the function. The result is attached. Look for the vertex and read the coordinates. (1,4) seems to work.
Answer:
Step-by-step explanation:
2y + 14x - 7x + 9y
2y + 9y + 14x - 7x
11y + 7x
Answer:
-11 1/4
Step-by-step explanation:
Answer: x= 5
Step-by-step explanation:
8x+32=1/5(25x−15)−4x
8x + 32 = <u>25x -15</u> - 4x <u><em>- 25x -15/ 5</em></u>
5
8x + 32 = 5x -3 - 4x
8x + 4x - 5x = -32 - 3
7x =-35
x = 35/7
x= 5
Answer:
No, because an expression is already solved and an equation is where you have to solve it
Step-by-step explanation: