<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
t H(t) g(t)
1 139 58.7
2 151 97.4
3 131 136.1
4 79 174.8
between 2nd and 3rd both are equal.
it shows they are at same height when t is between 2 and 3
Answer:
Step-by-step explanation:
Range from - infinite to - 2
The domain from - infinite to 5
Area of square = 5 x 5 = 25
area of trapezoid = 1/2(2+5)(4) = 28/2 = 14
area of figure = 25 + 14 = 39
answer
39 in^2
