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2 years ago

What is a factor pair of 72

Mathematics

2 answers:

Nataliya [291]2 years ago

8 0

Answer:

it is 72 and 1 , 36 and 2 , 3 and 24, 4 and 18, 6 and 12, 9 and 8.

Step-by-step explanation:

zubka84 [21]2 years ago

4 0

Hey there!

- Factor pair basically 2 factors that you multiply the given numbers to each other to get a given product (answer)

“Factors of 72”

- So we have to find MULTIPLES that gives you 72

Answers ⬇️

▸ 1 • 72 = 72

(SAME thing with 72 • 1 = 72)

▸ 2 • 36 = 72

(SAME with 36 • 2 = 72)

▸ 3 • 24 = 72

(SAME with 24 • 3 = 72)

▸ 4 • 18 = 72

(SAME with 18 • 4 = 72

▸ 6 • 12 = 72

(SAME with 12 • 6 = 72)

▸ 8 • 9 = 72

(SAME with 9 • 8 = 72)

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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katovenus [111]

Answer:

x = $\frac{7+\sqrt{47}\times i }{4}$

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6 ---------------(1)

y - 5 = $(x-2)^{2}$ ---------------(2)

y = $(x-2)^{2}$ + 5 ---------------(3)

Substitute (3) in (1) ,

x + 2( $(x-2)^{2}$ + 5 ) = 6

$(a + b)^{2}$ = $a^{2} + 2ab + b^{2}$

x + 2( $x^{2} - 4x + 4$ + 5 ) = 6

$2x^{2} - 7x + 12=0$ --------------(4)

The roots of the quadratic equation $ax^{2} +bx+c$ is

x = $\frac{(-b) + \sqrt{(-b)^{2}-4 \times ac } }{2 \times a}$ -----------(5)

According to equation (5),solution of (4) is

x = $\frac{7 + \sqrt{(-7)^{2}-4 \times 24 } }{2 \times 2}$

x = $\frac{7+\sqrt{49-96}}{4}$

x = $\frac{7+\sqrt{47}\times i }{4}$

4 0

3 years ago

Products produced by a machine has a 3% defective rate. What is the probability that the first defective occurs in the fifth ite

labwork [276]

Answer: The required probability is 0.1328.

Step-by-step explanation:

Since we have given that

n = 5

Probability of success = p = defective rate = 3% = 0.03

Probability of failure = q = 1-p = 1 - 0.03 = 0.97

So, we will use "Binomial distribution":

probability that the first defective occurs in the fifth item inspected would be

$P(X=1)=^5C_1(0.03)^1(0.097)^4\\\\P(X=1)=0.1328$

Hence, the required probability is 0.1328.

6 0

2 years ago