I've never been sure about how grades work but I believe it should be somewhere in the high 80's or low 90's
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Slope = 75
Y-intercept = 150
Answer: x= 8
Step-by-step explanation:
According to the converse of basic proportionality theorem,
If in ΔABC , DE is a line drawn from AB to AC such that 
then, DE is parallel to the third side BC.
Applying converse of basic proportionality theorem, to get NO parallel to KJ, we must have
Hence, the value of x should be 8, so that Line segment N O is parallel to line segment K J.
Answer:
I think the answer would be 60
Hope it was helpful .
Step-by-step explanation:
400 × 0.15 = 60
