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3 years ago

There are twelve rabbits in a cage. The ratio of white rabbits to all rabbits is 3:4. How many white rabbits are in a cage?

Mathematics

1 answer:

Rudik [331]3 years ago

3 0

First, set up a proportion.

$\frac{x}{12} = \frac{3}{4}$

Then, cross multiply and solve.

$36=4x36/4=99=x$

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What is the solution to the open sentence? 8y + 7 = y + 21 A. 2 B. 4 C. 7 D. 14

Airida [17]

8y+7= y+21
Subtract y from both side
7y+7=21
Subtract 7 from both sides
7y = 14
Divide both sides by 7
Y=2 or A

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3 years ago

Enter the unknown value that makes this statement true 40% of ______ is 60

SpyIntel [72]

40% of 150 is 60. That’s math

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3 years ago

Read 2 more answers

What is the Properties of Equality

Vesna [10]

Hi there,

Properties of Equality is two equations that have the same solution which are called equivalent equations. For example: 5+3=2+6 which all equal to 8.

In geometry, properties of Equality are the reflexive (2x=2x, a=a, b+1=b+1), symmetric (2a=3b then 3b=2a) and transitive property (if a+1=3 and 3=1-b, then a+1=1-b)

Hope this helped :)

Have a great day

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3 years ago

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notka56 [123]

Answer:

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3 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

3 years ago