Answer:
0.75 is it the answer
Step-by-step explanation:
Answer:
The answer to your question is: Ф = 43.95°
Step-by-step explanation:
Data
length = 18 ft
distance bottom to is 13 ft
x = angle = ?
Formula
cos Ф = opposite side / hypotenuse
Process
cos Ф = 13 ft / 18 ft substitution
cos Ф = 0.72 simplify
Ф = cos⁻¹ (0.72)
Ф = 43.95° result
Answer:
Scalene, Acute
Step-by-step explanation:
Scalene because each side has a different length
obtuse because one angle is more than 90°
Let x=3.77777777...
10x=37.777777777...
9x=10x-x=34
9x=34 so x=34/9=3 7/9
Given:
Capacity of jet plane = 200,000 liters of fuel
Fuel used during flight = 130,000 liters
To find:
The percentage of the fuel capacity it uses on this flight.
Solution:
According to the question, we need to find 130,000 is what percent of 200,000.



Therefore, the jet plane uses 65 percent of fuel capacity during flight.