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Rashid [163]
3 years ago
14

A analog clock (with hour and minute hands) is set to 5:00 P.M. After 30 min, what will the measure of the major arc formed by h

our and minute hands.
Mathematics
1 answer:
VikaD [51]3 years ago
4 0

Answer:

180 degrees

Step-by-step explanation:

Given

Time = 5:00pm

Required

The measure of the major arc, 30 minutes after

First, we calculate the time after 30 minutes

Time = 5:00pm +30\ mins

Time = 5:30pm

At 5:30pm, the hour and the minute hand will be directly opposite each other.

In other words, the hands divide the time into two equal parts (180 degrees each)

At this point, there is no major or minor arc as both sides have the same measurement

<em>Hence, the measure of the arcs is 180 degrees</em>

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The surface area of the prism below is 264 square units . Find the missing dimensions of this prism. ( picture is in the picture
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Answer:

The missing dimension is 4 units.

Step-by-step explanation:

In the given prism,

Of all the surfaces,

There are three rectangular surfaces and two triangular surfaces

<h2>Analyzing areas of rectangular surfaces:</h2>

1)The two rectangles with dimensions of 15 units and 5 units:

The area of each rectangle = Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 5 units.

Area of each rectangle = 15\times 5 ;

Area of each rectangle = 75 square units.

Sum of areas of the two rectangles = 2\times 75

Sum of areas of the two rectangles = 150 square units (equation 1)

2) The rectangle with the dimensions 15 units and 6 units:

The area of thus rectangle=  Length of rectangle \times Breadth of rectangle

From the diagram,

Length of rectangle = 15 units,

Breadth of rectangle = 6 units.

Area of the rectangle = 15\times 6 ;

Area of the rectangle = 90 square units. (equation 2)

From equation 1 and equation 2,

Therefore sum of areas of all rectangles in the prism = 150 + 90

Sum of areas of rectangles = 240 square units.

We also know,

Total surface area of the prism = Sum of areas of triangles + Sum areas of rectangles

Given, Total surface area of prism = 264 square units.

Therefore from the formula,

Sum of areas of triangles = Total surface area - sum of areas of reactangles

Sum of areas of triangles = 264 - 240

Sum of areas of triangles = 24 square units. (equation 3)

Let the missing dimension be 'h units'

<h2>Calculating sum of areas of triangles:</h2>

From diagram,both triangles are congruent,hence have the same area

Area of a triangle = \frac{1}{2}\times base\times height

From diagram,

Base = 6 units,

Height = h units.

Area of a triangle =\frac{1}{2}\times 6\times h = 3h square units.

Sum of the areas of both triangles = 3h+3h = 6h square units.

Using equation 3, we get

6h = 24;

h = \frac{24}{6}

Therefore,

h = 4 units.

Therefore,

The missing dimension is 4 units.

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