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Eduardwww [97]
3 years ago
7

21) Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the

Mathematics
1 answer:
diamong [38]3 years ago
6 0

Answer:

Step-by-step explanation:

Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the

race at 10 kmph. If his total time for the entire race was 1.74 hours, how far did he run in

the first part of the race?

First part :

Total Distance = 12 km

First part Speed = 8kmph

Let distance covered on first part = x

Second part speed = 10kmhr

(8*x)

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X = i don't know

Y = 50°

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2 years ago
Please help me
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Answer:

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2 years ago
1. Scientists estimate the rate of the wildebeest running at full speed to be 66 feet per second. Write a function rule to descr
lorasvet [3.4K]

1. d. d = 66t

The maximum speed of the wildebeest is v=66 ft/s. Speed is defined as the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

Re-arranging the formula, we get

d=vt

And substituting v=66 ft/s, we find

d=66t


2. c. y = 5 - n

In fact, we can check that this rule satisfies all the numbers of the sequence:

n=3 --> y = 5 - 3 = 2

n=4 --> y = 5 - 4 = 1

n=5 --> y = 5 - 5 = 0

n=6 --> y = 5 - 6 = -1


3. d. $5.50, $11.00, $16.50; E = 5.50h

In fact, if we use the rule E=5.50 h, we see that the table is completed as follows:

h=1 --> E=(5.50)(1 h)=5.50$

h=2 --> E=(5.50)(2 h)=11.00 $

h=3 --> E=(5.50)(3 h)=16.50$

h=4 --> E=(5.50)(4 h)=22.00$

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4. c. if d ≥ 5 then C = 4.70d, if d < 5 then C = 4.70d - 1; $17.80, $32.90

If the number of days is more than 5, the cost is 4.70$ per day, therefore c=4.70d (where d is the number of days); if the number of days is less than 5, one dollar is returned, so the cost will be C=4.70d-1. By applying this rule, we can calculate the rental cost after d=4 days and d=7 days:

- d=4 --> c=4.70*4-1=17.80$

- d=7 --> c=4.70*7=32.90$


5. b. y = 3x + 3

In fact, we can check this is the correct rule by substituting the numbers:

x=0 --> y=3*0+3=3

x=1 --> y=3*1+3=6

x=2 --> y=3*2+3=9

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7. x -2 -1 0 1 2

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The rule we have to apply is:

-10x + y = 4

Re-arranging it, we can solve for y:

y = 10x + 4

So, let's substitute the different values of x:

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x=0 --> 10*0+4= 4

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x=2 --> 10*2 +4 =20+4 = 24


8. y = -5x - 1

In fact, if substitute the different values of x given by the problem, we find:

x = -2 --> y = -5*(-2) -1= 10 -1 = 9

x = -1 --> y = -5*(-1) -1 = 5 -1 = 4

x = 0 --> y = -5*0 -1 = -1

x = 1 --> y = -5*1 - 1 = -6

x = 2 --> y = -5*2 -1 = -11


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Can a difference of two<br> square roots equal a<br> negative number?
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