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vovangra [49]
3 years ago
8

A. -3/2 b. 0 c. 3/2 d. DNE

Mathematics
1 answer:
mart [117]3 years ago
6 0
The answer would be cA
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In great detail, with full work done out, please find x<br> 1 + x = 2
kenny6666 [7]

Answer:

x = 1

Step-by-step explanation:

1 + x = 2

Subtract 1 form both sides,

1 + x - 1 = 2 - 1

       x  = 1

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2 years ago
(Find the distance between the points A(4, 3) and B(7,-1).​
lana66690 [7]

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5

Step-by-step explanation:

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A right triangle has a leg of 11 and a hypotenuse of 16. Find the missing leg (in simplest radical form)
wel

Answer: d

Step-by-step explanation:

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3 years ago
Hamdan says that when you add fractions with the same denominator, you can add the numerators and keep the same denominator. Is
Elina [12.6K]

Answer:

Yes, Hamdan is correct.

Step-by-step explanation:

Let the two fractions are q/r and s/r.

Here, the denominator is same for both the fractions.

So, as we add them, add the numerators and the denominators remains same.

\frac{q}{r}+\frac{s}{r}\\\\=\frac{q + s}{r}

For example

\frac{3}{5}+\frac{4}{5}\\\\=\frac{3 + 4}{5}\\\\=\frac{7}{5}

So, Hamdan is correct.

6 0
3 years ago
Find T, N, and B for the curve at the indicated point. [HINT: After finding T', plug in the specific value for t before computin
lyudmila [28]

Answer:

Step-by-step explanation:

Given that

r(t) = (t,t,e^t)

To find tangent, normal and binormal vectors at (0,0,1)

i) Tangent vector

r'(t) = (1,1,e^t)\\

At the particular point, r'(t) = (1,1,e)

Tangent vector = \frac{r'(t)}{||r'(t)||} \\=\frac{(1,1,e)}{\sqrt{1+1+e^2} } \\=\frac{(1,1,e)}{\sqrt{2+e^2} }

ii) Normal vector

T'(t) = (0,0,e^t)\\

At that point T'(t) = (0,0,e)/e = (0,0,1)

iii) Binormal

B(t) = TX N

= \left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)

8 0
3 years ago
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