A. -3/2<br> b. 0<br> c. 3/2<br> d. DNE

gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

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(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0

3 years ago

A store is having a sale where customers can buy one shirt and get a second shirt for 30% off. Kate wants to buy two shirts pric

siniylev [52]

Answer:

$32.3

Step-by-step explanation:

First write 30% in the decimal form

30/100 = 0.3

than the equation written in the form

x = 19 + (19 - 0.3× 19)

x = 19 + ( 19 - 5.7)

x = 19 + 13.3

x =$ 32.3

So, Kate will pay $32.3

5 0

2 years ago

A projectile is thrown upward so that its distance above the ground after t seconds is h = -16t^2 + 608t. After how many seconds

nordsb [41]

Answer:

I think the answer to your question is 19 seconds because if you do the math you get a vertex

Step-by-step explanation:

Using a calculator

5 0

3 years ago

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The distance from around the Earth along a given latitude can be found using the formula C=2∏r cos L , where r is the radius of

guajiro [1.7K]

Answer:

The distance reduces to 0 as you go from 0° to 90°

Step-by-step explanation:

The question requires you to find the distance using different values of L and check the trend of the values.

Given C=2×pi×r×cos L where L is the latitude in ° and r is the radius in miles then;

Taking r=3960 and L=0° ,

C=2× $\pi$ ×3960×cos 0°

C=2× $\pi$ ×3960×1

C=7380 $\pi$

Taking L=45° and r=3960 then;

C= 2× $\pi$ ×3960×cos 45°

C=5600.28 $\pi$

Taking L=60° and r=3960 then;

C=2× $\pi$ ×3960×cos 60°

C=3960 $\pi$

Taking L=90° and r=3960 then;

C=2× $\pi$ ×3960×cos 90°

C=2× $\pi$ ×3960×0

C=0

Conclusion

The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant

7 0

3 years ago

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7. What is the slope of the line that passes through the pair of points (3, 8) and (9, 5) ? (1 point)

agasfer [191]

7. D
8. D
9. D
10.C

for 7 & 8 you use the equation
$\frac{y2 - y1}{x2 - x1}$
your points are (3,8) & (9,5)

so you plug the numbers in
y2= 5
y1=8

x2=9
x1=3
you subtract them get a fraction and that is your slope

9 & 10
use the equation
$y - y1 = m(x - x1)$
plug you numbers in for y1 and x2 m is your slope plug it in and that is your equation

5 0

3 years ago

Read 2 more answers

A. -3/2 b. 0 c. 3/2 d. DNE