Answer:
![y=\frac{7}{2}x-20](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B7%7D%7B2%7Dx-20)
Step-by-step explanation:
Let the equation of the line be
where, 'm' is its slope and
is a point on it.
Given:
The equation of a known line is:
![y=-\frac{2}{7}x+9](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B2%7D%7B7%7Dx%2B9)
A point on the unknown line is:
![(x_1,y_1)=(4,-6)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%284%2C-6%29)
Both the lines are perpendicular to each other.
Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is ![m_1=-\frac{2}{7}](https://tex.z-dn.net/?f=m_1%3D-%5Cfrac%7B2%7D%7B7%7D)
When two lines are perpendicular, the product of their slopes is equal to -1.
Therefore,
![m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}](https://tex.z-dn.net/?f=m%5Ccdot%20m_1%3D-1%5C%5Cm%3D-%5Cfrac%7B1%7D%7Bm_1%7D%5C%5Cm%3D-%5Cfrac%7B1%7D%7B%5Cfrac%7B-2%7D%7B7%7D%20%7D%3D%5Cfrac%7B7%7D%7B2%7D)
Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,
![y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20](https://tex.z-dn.net/?f=y-%28-6%29%29%3D%5Cfrac%7B7%7D%7B2%7D%28x-4%29%5C%5Cy%2B6%3D%5Cfrac%7B7%7D%7B2%7Dx-14%5C%5Cy%3D%5Cfrac%7B7%7D%7B2%7Dx-14-6%5C%5C%5C%5Cy%3D%5Cfrac%7B7%7D%7B2%7Dx-20)
The equation of a line perpendicular to the given line and passing through (4, -6) is
.
If you would like to write x = 1/3 * y in general form, you can do this using the following steps:
The general form of the equation is: ax + by + c = 0.
x = 1/3 * y
x - 1/3 * y = 0
The correct result would be x - 1/3 * y = 0.
C. The lower quartile (of a box-and-whisker plot) is the median of the lower half of the data.
Also referred to as "Q1"
The amount of different combos possible would be 165 // Hope this helped, comment below for any clarifications // Brainliest ;) Thanks!! //
Your question seems to be incomplete