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3 years ago

Find the arc length of the semicircle

Mathematics

2 answers:

sukhopar [10]3 years ago

4 0

Answer:

18.8496 units (rounded o1ff to four decimal places)

Step-by-step explanation:

Arc length = 2 × π × r × $\frac{central-angle}{360}$

r (radius) = 12 units ÷ 2 = 6 units

Central angle = 180°

For our semicircle, the arc length = 2 × π × 6 × $\frac{180}{360}$ = 18.8495559215 units

Or 18.8496 units (rounded o1ff to four decimal places)

Sergeeva-Olga [200]3 years ago

4 0

Answer:

6pi

Step-by-step explanation:

hop it helps

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1 2.2.5 Quiz: Volume

LUCKY_DIMON [66]

Answer:

12 1/2 cubic units, the formula is Lenght × Width × Hieght

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3 years ago

The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

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3 years ago

Help please what is the slope?

Harlamova29_29 [7]

Answer:

The slope is 3 and it's positive

Step-by-step explanation:

(2, 5) and (3, 8)

m=(y2-y1)/(x2-x1)

m=(8-5)/(3-2)

m=3/1

m=3

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3 years ago

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How to solve Which ordered pair is a solution for x − 3y = 1?

babunello [35]

There is no one answer (ordered pair) to this equation and the answer is found by graphing or trying out different values for each variable. Anyway, here are some solutions; (1,0), (4,1), (0,-1/3).

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3 years ago

20 cm

lawyer [7]

The area of the arrow given in the figure is 610 square cm

<h3>Area of composite figure</h3>

The given figure is made up of rectangle and triangle. The area is expressed as:

Area = Area of rectangle + area of triangle

Substitute the given parameters

Area of the arrow = (15*20) + 0.5(31 * 20)

Area of the arrow = 300 + 310
Area of the arrow = 610 square cm

Hence the area of the arrow given in the figure is 610 square cm

Learn more on area of composite figures here: brainly.com/question/21135654

#SPJ1

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2 years ago