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3 years ago

A line with a slope of -8/3

Mathematics

1 answer:

strojnjashka [21]3 years ago

7 0

Answer:

y = - $\frac{8}{3}$ x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mc + c ( m is the slope and c the y- intercept )

Here m = - $\frac{8}{3}$ and crosses the y- axis at (0, 10 ) ⇒ c = 10

y = - $\frac{8}{3}$ x + 10 ← equation of line

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3 years ago

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Brut [27]

Answer and Step-by-step explanation: (MAKE ME BRAINLIEST)

Simplified version

1) √14/6

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3 years ago

3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl

riadik2000 [5.3K]

Elimination Method

$\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}$

If we multiply the equation 3 by (-1) we obtain this:

$\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}$

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

$\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\ \end{gathered}$

2. We can replace this value of X in the 1st and 2nd equations

$\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}$

3. If we simplify:

$\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}$

4. We can obtain Y from this two equations:

$\begin{gathered} Y=-\frac{-12Z+58}{9} \\ \end{gathered}$

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

$\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}$

6. If we simplify, we obtain:

$X=\frac{-3Z+7}{9}$

7. In conclusion, we obtain that

(X,Y,Z) =

$(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)$

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1 year ago

Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = (x − a)(x − b). Describe

MatroZZZ [7]

Answer:

1) The parabola equation faces up

2) The y-intercept = a·b

3) The zeros are x = a and x = b

Step-by-step explanation:

1) The given information are;

f(x) = (x - a)·(x - b) which gives;

f(x) = x² - (b+a)·x + a·b

For an equation of the form a·x² - b·x + c, if a is positive, then the parabola faces up, therefore, the parabola equation, x² - (b+a)·x + ab where a is equivalent to +1 faces up

2) The y-intercept is given at x = 0, which gives;

f(0) = 0² - (b+a)·0 + a·b

The y-intercept = a·b

3) From f(x) = (x - a)·(x - b), when f(x) = 0, we have either;

(x - a) = 0 or (x - b) = 0

Therefore;

The zeros are x = a and x = b

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The average was 8.3 meters/second

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3 years ago

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