Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion: 
Significance level : 
Critical z-value :
(using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

i.e. 
i.e. 
i.e. 
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)
B. 1/2(6x-12) = 3x -6 = 3(x-2)
D. 12x -18 + 2 = -16+12x
12x -16 = -16+ 12x
B and D are the answers
Trust me
Hope this helps!
Mark me as brainliest if you can, I really appreciate it!
Answer:
56
Step-by-step explanation:
8 cupcakes per 1 cup of flower
56 cupcakes per 7 cups of flower
times both by 7
Answer:
if t=60, then 6(60)/9-23. (360-198)/9
=18