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aksik [14]
3 years ago
11

AWARDING BRAINLIEST

Physics
1 answer:
Airida [17]3 years ago
3 0

Answer:

The first one.

Explanation:

At least I believe so-

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A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2010 × 103 seconds (about
vazorg [7]

Answer:

Radial acceleration of moon is a_{r} = 2.246\times 10^{-3}\frac{m}{s^{2} }

Explanation:

Given :

Time period T = 1.987 \times 10^{6} sec

Distance from center of moon to planet r = 225 \times 10^{6} m

From the equation of radial acceleration,

  a_{r} = r\omega ^{2}

Where \omega = 2\pi f = \frac{2\pi }{T}

So   \omega = 3.16 \times 10^{-6} \frac{rad}{s}

Now moon's radial acceleration,

 a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}

 a_{r} = 2246.76 \times 10^{-6}

 a_{r} = 2.246\times 10^{-3} \frac{m}{s^{2} }

7 0
3 years ago
Which of the following statements is true for a cell placed in beaker containing an isotonic solution?
Korvikt [17]
An isotonic solution is <span>a solution in which concentration or solute is equal to that of a cell placed in it. Thus, the system is in dynamic equilibrium, and so water molecules flow in both directions.
The correct answer is <u>C. w</u></span><span><u>ater molecules flow in both directions at the same rate.</u></span>
3 0
4 years ago
A downward force of magnitude 5 n is exerted on the book by the force of.
WINSTONCH [101]

Answer:

A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...

6 0
2 years ago
A piece of plastic with a mass of 15 g is
satela [25.4K]

Answer:

The density of plastic is equal to 0.6 g/mL.

Explanation:

Given that,

The mass of piece of plastic, m = 15 g

It is placed in a graduated cylinder. The water  level in the graduated cylinder rises from  30 mL to 55 mL when the plastic is added.

We need to find the density of plastic.

Rise in volume = 55 mL - 30 mL

= 25 mL

The density of an object is given by :

d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{25\ mL}\\\\d=0.6\ g/mL

So, the density of plastic is equal to 0.6 g/mL.

5 0
3 years ago
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