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enyata [817]
3 years ago
7

A boy is pulling a 150 kg crate with a force of 1150 N. If the crate experiences a frictional force of 490 N, find:

Physics
1 answer:
valentina_108 [34]3 years ago
7 0
<h3><u>For the aceleration:</u></h3>

First, let's find the resultant, and <u>applicate 2nd law of Newton</u> using the resultant, so:

R = ma

F - Ff = ma

Data:

F = Force = 1150 N

Ff = Friction force = 490 N

m = Mass = 150 kg

a = Aceleraction = ?

Replacing according our data:

1150 N - 490 N = 150 kg * a

660 N = 150 kg * a

660 N / 150 kg = a

a = 4,4 m/s²   ← Aceleration of the object

<h3><u>For the normal force:</u></h3>

The normal force IS NOT the resultant force, the normal force's the force between the ground and the object, in another words, is the weight of the object, and for the weight:

w = mg

w = 150 kg * 10 m/s²

w = 1500 N   ← Normal force between object and ground.

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98 POINTS FOR ANYONE THAT DOES THIS NOW!!
Varvara68 [4.7K]

In simpler terms, a proton and neutron weigh 1 amu (atomic mass unit) each.

The nucleus has 15 protons and 18 neutrons. Since a proton's and a neutron's weight is only 1 amu, we can simply add the number of protons and neutrons to find the total mass of the nucleus:

15 + 18 = \boxed{33}

The nucleus' mass is 33 amu.

8 0
3 years ago
Read 2 more answers
How does the amount of energy coming from the energy source (low vs. high) affect the amount of electrical energy created?
Ugo [173]

Answer:

The environmental problems directly related to energy production and   Electricity is a secondary energy source that is generated  producedfrom primary energy sources:

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3 0
2 years ago
7. 100 Joules of work was done to move an object with a force of 15 N. How far did the
worty [1.4K]

Answer:Distance=6.67 (rounded)

Explanation: Work = Force x Distance.

100 Joules of work= force of 15 N x Distance (?)

The work equation given above can be rearranged to find force or distance if the other variables are known:

Distance=Work / force

Distance=100Joules/15 N

Distance=6.67 (rounded)

7 0
3 years ago
The position of a particle moving along an x axis is given by x = 14.0t2 - 2.00t3, where x is in meters and t is in seconds. det
Mumz [18]

a) x = 14t^{2} -2t^{3}

at t = 5s

x = 14*5^{2} -2*5^{3} = 14*25 - 2*125 = 350 - 250 = 100 m

b) v = \frac{dx}{dt}

       = 28t - 6t^2

at t = 5 s

v = 28*5-6*25 = 140 - 150 = -10 m/s

c) a = \frac{dv}{dt}

     = 28 - 12t

at t = 5 s

a = 28 -12*5= 28-60= -32 m/s^2

d) At maximum positive coordinate velocity = 0

So, 0 = 28t - 6t^2

         t = \frac{28}{6} = \frac{14}{3} = 4.66 s

  At t = 4.66 s

   X = 14 * 4.66^2 - 2* 4.66^3 = 202.39  m

e) At t = 4.66 s

f) At maximum positive velocity a = 0

   0=28-12t

   t = \frac{28}{12} = \frac{7}{3} = 2.33 s

At t = 2.33 s

V = 28*2.33- 6*2.33^2= 32.67 m/s

g) t = 2.33 s

h) When particle is not moving v = 0

So 0= 28t - 6 t^2

 t = \frac{28}{6} = 4.66 seconds

At t = 4.66 s

a = 28 - 12 * 4. 66 = -27.93m/s^2

i) At t = 0s, X =0m

       t = 5s, X = 100m

So, Displacement = 100m

Velocity = \frac{Displacement}{Time}  = \frac{100}{5} = 20m/s

8 0
3 years ago
1 point
marta [7]

Answer:

Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.

Hence, for series combination of resistances,

R

s

=2R

And for parallel combination of resistances,

R

p

=

2

R

Now, heat produced when they first connected in series is

H

s

=

R

s

V

2

where, V is voltage supplied to the heater.

H

s

=

2R

V

2

.....................................(1)

heat produced when they first connected in series is

H

p

=

R

p

V

2

H

p

=

2

R

V

2

H

p

=

R

2V

2

............................................(2)

From (1) and (2), we get

H

p

H

s

=

R

2V

2

2R

V

2

⇒

H

p

H

s

=

4

1

7 0
3 years ago
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