Student B is wrong , student A is correct in simplifying the expression .
Expression B must be simplified to cot θ .
Formulas to be used are :
1 -
θ =
θ
1 -
θ =
θ .
Since , location of error is step 3 , we will start from there
[ ( 1 -
θ ) / sin θ ] / cos θ = [ ( 1 -
θ ) / sin θ ] * [ 1 / cos θ ]
= ( 1 -
θ ) / ( sin θ * cos θ )
=
θ / ( sin θ * cos θ )
= cot θ .
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Since , the question is incomplete we assume it to be :
The answer as a fraction is 6/11
PQ would be 4 square root 6 times square root of 2, which is also 4 square root 12. Simplified, it would be 8 square root 3
Answer:
f(0)= 3-2^0 --> 3-1 =2
f(-1)= 3 - 2^-1 --> 3 - 1/2 -->5/2 = 2,5
Step-by-step explanation: F(0) means if x=0 so the first you just take x and replace it with 0 and the second you replace x by -1.
Something that is elevated by 0 is always going to be 1
Hope this make sense :)