The horse traveled 439.6 feet after walking around the track 5 times
<u><em>Solution:</em></u>
Given that, horse walks around a circular track while its trainer stands in the center
The trainer is 14 feet from the horse at all times
Therefore, radius of circular track = 14 feet
The circumference of circle is the distance traveled by horse for 1 lap
<em><u>The circumference of circle is given as:</u></em>
![C = 2 \pi r](https://tex.z-dn.net/?f=C%20%3D%202%20%5Cpi%20r)
Where, "r" is the radius and
is a constant equal to 3.14
![C = 2 \times 3.14 \times 14\\\\C = 87.92](https://tex.z-dn.net/?f=C%20%3D%202%20%5Ctimes%203.14%20%5Ctimes%2014%5C%5C%5C%5CC%20%3D%2087.92)
Thus the distance traveled by horse for one time in circular track is 87.92 feet
<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>
Multiply the circumference by 5
![distance = 5 \times 87.92\\\\distance = 439.6](https://tex.z-dn.net/?f=distance%20%3D%205%20%5Ctimes%2087.92%5C%5C%5C%5Cdistance%20%3D%20439.6)
Thus the horse traveled 439.6 feet after walking around the track 5 times
The answer is x=s-3 (x is her age)
Answer:
y=58x+460
Step-by-step explanation:
y=mx+b
We are given m=58 so we have
y=58x+b
We are given (-8,-4) is a point on the line.
-4=58(-8)+b
-4=-464+b
460=b
So the line in slope intercept form is y=58x+460
-5x - 49 > 113
Add 49 to both sides
-5x > 162
Divide both sides by -5
x > -32.4
Hope this helps!