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Karolina [17]
3 years ago
5

Example 6

Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

The answer is below

Step-by-step explanation:

1. COST Mr. Rivera wants to purchase a riding lawn mower, which is on sale for 15% off the marked price.  The store charges sales tax 6.5% on all sales. Write a  function p(x) that represents the price after a 15%  discount. Write a function t(x) that represents the total  cost with sales tax. Write a composition of functions that  represents the total cost of a riding lawn mower on sale.  How much will Mr. Rivera pay for a riding lawn mower  that has a marked price of $3000?

Solution:

a) Let x represent the marked price and p(x) represent the price after discount. Since a discount of 15% is given, the price would be:

p(x) = x(100\% -15\%)=x(1-\frac{0.15}{100} )=0.85x

b) If x = discounted price and t(x) = total  cost with sales tax, then:

t(x) = x(100\% +6.5\%)=x(1+\frac{6.5}{100} )=1.065 x

c) Let t(x) represents the total  cost with sales tax

t[p(x)] =p(x)+6.5\%\ of\ p(x) \\\\t[p(x)] = 0.85x+(0.065*0.85x)\\\\t[p(x)] =0.90525x\\\\for\ x=\$3000:\\\\t[p(3000)] = 0.90525*3000=\$2715.75

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Name an angle bisector shown in the figure.<br><br><br> DE<br><br> AB<br><br> GB<br><br> CF
expeople1 [14]

Answer:

CF

Step-by-step explanation:

we know that

An <u><em>angle bisector</em></u> is a line that divide an angle into two equal angles.

In this problem

m\angle ACF=m\angle FCD ---> given problem

m\angle ACD=m\angle ACF+m\angle FCD ---> by addition angle postulate

so

CF is an angle bisector of angle m\angle ACD

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6) Sally wrote the number 30, 048 in expanded form.
vichka [17]

Answer:

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3 years ago
Find pb, if pj=14 and jb= 28
anyanavicka [17]

Answer:

42

Step-by-step explanation:

Based on the information given, point j is the midpoint, as it is shared by both line segments. Set the equation:

pb = pj + jb

Note:

pj = 14

jb = 28

Plug in the corresponding numbers to the corresponding variables:

pb = pj + jb

pb = 14 + 28

pb = 42

pb = 42 is your answer.

~

3 0
3 years ago
Read 2 more answers
Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
Read 2 more answers
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