Answer will be no A I think that
Answer:
Step-by-step explanation:
A parallelogram is a quadrilateral with two pairs of parallel sides. Opposite sides of a parallelogram are equal.
Therefore, set any two opposite sides equal to each other to solve for 
:
64*2 is 128
1/2 of a cup of chocolate powder is 64g
laura added 4/6 of a cup
laura went over by 1/3 of a cup
This is not correct because 6.5% of 25 is 1.63
Hat point in the feasible region maximizes the objective function
<span>constraints: </span>
<span>x>=0 </span>
<span>y>=0 </span>
<span>-x+3>=y </span>
<span>y<=1/3 x+1 </span>
<span>Objective function: C=5x-4y </span>
<span>1. Region limited by : </span>
<span>x>=0 </span>
<span>y>=0 </span>
<span>x + y <= 3 </span>
<span>is the interior of rectangle triangle </span>
<span>of summits (0,0), (0,3)and (3,0) </span>
<span>if we add the constraint </span>
<span>y <= 1/3 x + 1 </span>
<span>it's the part in the triangle below this line : </span>
<span>the summits are (0,0) , (0,1) , (3,0) </span>
<span>and the intersection point of </span>
<span>line L of equation : y = x/3 + 1 and the hypotenuse </span>
<span>of the triangle (equation x+y = 3) </span>
<span>let's solve this : </span>
<span>3 - x = x/3 + 1 </span>
<span>4x/3 = 2 </span>
<span>x = 3/2 and y = 3/2 </span>
<span>now the Criteria : C = 5x - 4y </span>
<span>are lines parallel to line of equation </span>
<span>5x - 4y = 0 </span>
<span>or </span>
<span>y = (5/4)x </span>
<span>so C is maximum at an edge of the domain : </span>
<span>points are </span>
<span>O ( 0 ,0) </span>
<span>A( 3 , 0) </span>
<span>B ( 0 ; 1) </span>
<span>D ( 3/2 ; 3/2) </span>
<span>criteria is C = 5x - 4y </span>
<span>C (A) = 5*3 - 4*0 = 15 </span>
<span>C(B) = 5*0 - 4*1 </span>
<span>C(D) = 5* (3/2) - 4*(3/2) = 3/2 </span>
<span>so C is max at point A(3 ; 0)</span>
