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2 years ago

Pls help on my maths question

Mathematics

1 answer:

dimulka [17.4K]2 years ago

8 0

Answer:

Somewhat illegible but looks like the equation should be:

S = u t + 1/2 a t^2

100 = 20 + 1/2 * a * 4 where t = 2

a* 4 = 160

a = 40

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$18.99 CD; 15% discount

jekas [21]

Answer:

15% discount is

15/100 × 18.99 = 2.85

The sale price with discount is 18.99 - 2.85 = 16.14

8 0

2 years ago

Taylor, Moore, and Jenkins are candidates for public office. It is estimated that Moore and Jenkins have about the same probabil

katrin [286]

Answer:

Taylor = 50%

Moore = 25%

Jenkins = 25%

Step-by-step explanation:

Assuming there are no other candidates and that someone has to win the election, the probabilities of Taylor, Moore, and Jenkins winning the election must add up to 1 or 100%.

$T+M+J = 1\\$

Since Moore and Jenkins have about the same probability of winning, and Taylor is believed to be twice as likely to win as either of the others:

$M=J\\T=2J\\J+J+2J=1\\J=0.25\\M=J=0.25\\T=2*0.25=0.5$

Taylor has a probability of 50% of winning the election.

Moore has a probability of 25% of winning the election.

Jenkins has a probability of 25% of winning the election.

3 0

2 years ago

Volume of the cylinder with diameter of 8mm and height of 8mm

alexdok [17]

Answer:

V = 402.12385mm

Step-by-step explanation:

When the diameter is 8mm, the radius is 4mm.

V = (π(4^2))8

V = (16π)8

V = (50.2654)8

V = 402.12385

V ≈ 402, 402.1, 402.12, 402.124

4 0

2 years ago

An open metal tank of square base has a volume of 123 m^3

snow_lady [41]

Answer:

a) h = 123/x^2

b) S = x^2 +492/x

c) x ≈ 6.27

d) S'' = 6; area is a minimum (Y)

e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

123 = x^2·h

h = 123/x^2

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

$S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}$

c) The derivative of the area with respect to x is ...

$S'=2x-\dfrac{492}{x^2}$

When this is zero, area is at an extreme.

$0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583$

d) The second derivative is ...

$S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6$

This is positive, so the value of x found represents a minimum of the area function.

e) The minimum area is ...

$S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78$

The minimum area of metal used is about 117.78 m².

3 0

2 years ago

Help,, i'll mark as brainliest

PtichkaEL [24]

The first question would be distance from the start, as it is steadily going up as time goes on.

The second question would be distance from the end, as it is steadily going down as time goes on.

The third question would be speed, as the speed is staying stable as shown by the straight lines seen within the distance from start/end graphs being linear lines.

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2 years ago