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ipn [44]
3 years ago
6

5c+cd when c =1/5 and d=15

Mathematics
2 answers:
Fynjy0 [20]3 years ago
4 0

Answer:

4

Step-by-step explanation:

5(1/5)+(1/5)(15)

5/5+15/5

1+3

4

Leni [432]3 years ago
4 0

Answer:

4

Step-by-step explanation:

Evaluate 5 c + c d where c = 1/5 and d = 15:

5 c + c d = 5/5 + 1/5×15

5/5 = (5×1)/5 = 1:

1 + 3

15/5 = (5×3)/5 = 3:

3 + 1

1 + 3 = 4:

Answer: 4

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3 years ago
Subject: Mathematics
lina2011 [118]

\\ \sf\longmapsto \dfrac{1}{x-1}>4

  • Multiply x-1 on both sides

\\ \sf\longmapsto \dfrac{1}{x-1}\times (x-1)> 4(x-1)

\\ \sf\longmapsto 1>4(x-1)

\\ \sf\longmapsto 1> 4x-4

  • Add 4 on both sides

\\ \sf\longmapsto 1+4> 4x

\\ \sf\longmapsto 5> 4x

  • Divide both sides by 4

\\ \sf\longmapsto \dfrac{5}{4}>x

\\ \sf\longmapsto x< \dfrac{5}{4}

Now

ATQ to the equation \bf \dfrac{1}{x-1} x should be greater than 1 .Because if it becomes 1 then the denominator will be 0 which is impossible.

Hence x>1

Thus

\\ \sf{:}\!\implies 1

Now

\\ \therefore\boxed{\bf x\epsilon \left(1,\dfrac{5}{4}\right)}

6 0
3 years ago
Read 2 more answers
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