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3 years ago

5c+cd when c =1/5 and d=15

Mathematics

2 answers:

Fynjy0 [20]3 years ago

4 0

Answer:

Step-by-step explanation:

5(1/5)+(1/5)(15)

5/5+15/5

1+3

Leni [432]3 years ago

4 0

Answer:

Step-by-step explanation:

Evaluate 5 c + c d where c = 1/5 and d = 15:

5 c + c d = 5/5 + 1/5×15

5/5 = (5×1)/5 = 1:

1 + 3

15/5 = (5×3)/5 = 3:

3 + 1

1 + 3 = 4:

Answer: 4

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$\\ \sf\longmapsto \dfrac{1}{x-1}>4$

Multiply x-1 on both sides

$\\ \sf\longmapsto \dfrac{1}{x-1}\times (x-1)> 4(x-1)$

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$\\ \sf\longmapsto 1> 4x-4$

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$\\ \sf\longmapsto 1+4> 4x$

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Divide both sides by 4

$\\ \sf\longmapsto \dfrac{5}{4}>x$

$\\ \sf\longmapsto x< \dfrac{5}{4}$

Now

ATQ to the equation $\bf \dfrac{1}{x-1}$ x should be greater than 1 .Because if it becomes 1 then the denominator will be 0 which is impossible.

Hence x>1

Thus

$\\ \sf{:}\!\implies 1$

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$\\ \therefore\boxed{\bf x\epsilon \left(1,\dfrac{5}{4}\right)}$

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3 years ago

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