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2 years ago

Solve for x and find the missing angles.

Mathematics

2 answers:

jolli1 [7]2 years ago

8 0

X=8 and and missing angles are 140

JulsSmile [24]2 years ago

7 0

Answer:

5x = 2x + 24 ( opposite angles are equal)

5x - 2x = 24

3x = 24

x = 24/3

x = 8

5x = 5 × 8 = 40

2x + 24 = 2(8)+24 = 16 +24 = 40

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What is the median of the following numbers 45,36,52,55,47, 39

Elena L [17]

Answer:

Step-by-step explanation:

By arranging the numbers from least to greatest, you can find the median by locating the central number in the data set.

8 0

3 years ago

Simplify<br> CLEAR Step By Step Explanation Please. <br> Will Mark Brainliest

siniylev [52]

Answer:

1/x+5

Step-by-step explanation:

1. Rewrite 3x as a difference

x-2/x^2 + 5x-2 - 10

2. Factor out x from the equation, then factor out -2.

x-2/ x+(x+5) - 2(x+5)

3. Factor out x+5 from the expression

x-2/ (x+5)(x-2)

4. Reduce the fraction with x-2

x-2 / (x+5) x-2

1/x+5

8 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is </u></em>

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

60% of what number is 33?

Andreyy89

Answer:

Step-by-step explanation:

33/60 = 0.55 * 100 = 55

Check:

55*0.6 = 33

Hope that helps!

8 0

2 years ago

A line with a slope of 3 passes through the point (2, 5). Write an equation for this line in point-slope form.

Phantasy [73]

Answer:

slope = 3

point (2, 5)

b = y - m*x

b = 5 -3*2

b = -1

Then we enter the slope and the value of b into this equation:

y = mx + b

y = 3x -1

Source: https://www.1728.org/distance.htm

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers