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Julli [10]
2 years ago
9

Find the two x-intercepts of the function f and show that f '(x) = 0 at some point between the two x-intercepts.

Mathematics
1 answer:
suter [353]2 years ago
7 0

Step-by-step explanation:

f(x) = x√(x+8)

When f(x) = 0,

0 = x√(x+8)

x = 0, x + 8 = 0

x = -8

f'(x) = (1)√(x+8) + x • ½(x+8)^(-½) = 0

0 = √(x+8) + 1/[2√(x+8)] (x)

-2(x+8) = x

-2x - 16 = x

x = -16/3

(-8 < -16/3 < 0)

Therefore, x-intercept of f'(x) = 0 is somewhere between the two x-intercepts, ranging from -8 to 0.

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Step-by-step explanation:

$78.75/5 hr=$15.75/hr

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What is the correct evaluation of 3x2 + 4x - 2y2 + 4y + 5, when x is equal to -1 and y is equal to 5?
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8 0
3 years ago
in a test consisting of 90 questions, Ama answered 75% of the first 40 questions correctly. If she had to get a score of 80% in
Shalnov [3]

Answer:

total question =90

she obtained 75% of first 40 questions

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2. in order to get 80% out of 90,

the no. of questions got correct by Ama = 80% * 90 = 72

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Step-by-step explanation:

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