I think it is -14. I inserted 4 as n. I don't know if that's how you do it.
The volume of the entire rocket given the volumes of the cylindrical body and the cone nose is 117.23 in³.
<h3>What is the volume of the entire rocket?</h3>
The volume of the entire rocket is the sum of the volume of the cylinder and the volume of the cone.
Volume of the cylinder = πr²h
Where:
- π = 3.14
- r = radius 2
- h= height = 12 - 4 = 8 inches
3.14 x 2² x 8 = 100.48 in³
Volume of the cone = 1/3 πr²h
1/3 x 2² x 3.14 x 4 = 16.75 in³
Volume of the rocket = 100.48 + 16.75 = 117.23 in³
To learn more about the volume of a cone, please check: brainly.com/question/13705125
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Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
