Use this rule: <em>(x^a)^b = x^ab</em>
3(x + 2)^3/5 + 2 = 27
Subtract 3 from both sides
3(x + 2)^3/5 = 27 - 3
Simplify 27 - 3 to 24
3(x + 2)^3/5 = 24
Divide both sides by 3
(x + 2)^3/5 = 24/3
Simplify 24/3 to 8
(x + 2)^3/5 = 8
Take the cube root of both sides
x + 2 = 3/5√8
Invert and multiply
x + 2 = 8^5/3
Calculate
x + 2 = 2^5
Simplify 2^5 to 32
x + 2 = 32
Subtract 2 from both sides
x = 32 - 2
Simplify 32 - 3 to 30
<u>x = 30</u>
I don't know if you have multiple choices, but it could be: 2x-9
Two small rectangle at the end areas are:
3x5=15
15x2=30
Longer middle rectangle is:
Length:5+3+5+3=16
Width:9
16x9=144
30+144=174
The lengths of the sides are 7, 23 and 24.
In order to find this, we need to add all of the side lengths together and set equa to 54. This will allow us to solve for n.
n + 3n + 2 + 4n - 4 = 52
8n - 2 = 52
8n = 54
n = 7
This gives us the length of the first side. To solve for the others, plug 7 into the equations.
3n + 2
3(7) + 2
21 + 2
23
Then the next one.
4n - 4
4(7) - 4
28 - 4
24
Answer:
its 2 1/2 its width
Step-by-step explanation:
