Find the lowest common denominator. 1/(x+2)^2, 1/(x-2)^2, 2/(x^2-4) A. (x+2)^2 (x-2)^2 B. (x^2+2) (x^2-2)
2 answers:
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Answer:
y = 16
Step-by-step explanation:
Given that y varies directly as x then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = 48 when x = 6, thus
k = =
= 8
y = 8x ← equation of variation
When x = 2, then
y = 8 × 2 = 16