Find the lowest common denominator. 1/(x+2)^2, 1/(x-2)^2, 2/(x^2-4) A. (x+2)^2 (x-2)^2 B. (x^2+2) (x^2-2)
2 answers:
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Answer:
Step-by-step explanation:
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Answer:
i) Equation can have exactly 2 zeroes.
ii) Both the zeroes will be real and distinctive.
Step-by-step explanation:
is the given equation.
It is of the form of quadratic equation and highest degree of the polynomial is 2.
Now, FUNDAMENTAL THEOREM OF ALGEBRA
If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.
So, the equation can have exact 2 zeroes (roots).
Also, find discriminant D =
⇒ D = 37
Here, since D > 0, So both the roots will be real and distinctive.