Answer:
Minimum 66 feet of molding that he needs.
Step-by-step explanation:
Given that a square ceiling has a diagonal of 23 ft.
If the sides of the square ceiling are 'a' feet, then applying Pythagoras Theorem we can write, a² + a² = 23²
⇒ 2a² = 23²
⇒ a = 16.2634 feet (Approximate)
Now, the perimeter of the square ceiling will be 4a = 65.05 feet.
If the cost of molding along the perimeter of the ceiling is in per foot, then a minimum of 66 feet of molding that he needs. (Answer)
Answer:
I think it is either 1/6 or 1/8
Hope it helps :)
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
Learn to solve more word problems here: brainly.com/question/2610134
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Answer:
4 4/5
Step-by-step explanation:
Answer:
6-3c-C
Step-by-step explanation:
3(2-c)-C
3(2)-3(c)-C
6-3c-C
