Let the length of the rectangle be L and the width be W.
Given that the length is twice the width, Then :
L = 2W .....(1)
But we know that the perimeter is 36.
==> 2L + 2W = 36
==> 2L + L = 36
==> 3L = 36
==> L = 36/3 = 12
==> W = 12/2 = 6
Now we will calculate the area:
==> A = L * W = 12* 6 = 72 square feet.
<span>Then the area of the rectangle is 72 square feet.</span>
<span>I am 100% sure that that would be the answer!!</span>
<span>have fun!!1</span>
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<h3>
Answer:</h3>
- a_n = -3a_(n-1); a_1 = 2
- a_n = 2·(-3)^(n-1)
<h3>
Step-by-step explanation:</h3>
A) The problem statement tells you it is a geometric sequence, so you know each term is some multiple of the one before. The first terms of the sequence are given, so you know the first term. The common ratio (the multiplier of interest) is the ratio of the second term to the first (or any term to the one before), -6/2 = -3.
So, the recursive definition is ...
... a_1 = 2
... a_n = -3·a_(n-1)
B) The explicit formula is, in general, ...
... a_n = a_1 · r^(n -1)
where r is the common ratio and a_1 is the first term. Filling in the known values, this is ...
... a_n = 2·(-3)^(n-1)
3-b) 216²/³ = ∛216² = ∛(6x36)² = 36
3-c) 256⁻¹/⁴ = 1/(256¹/⁴) = 1/(⁴√256) = 1/4
4/12 = 2/6 if you simplify it into a smaller fraction ok
Answer:
Its A
Step-by-step explanation:
