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2 years ago

Pls help I need help thank u

Mathematics

2 answers:

antoniya [11.8K]2 years ago

7 0

27, just did the math.

padilas [110]2 years ago

3 0

Answer:

Step-by-step explanation:

I did it before

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sin23/6.2 = sin85/b

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Which of the following is the correct point-slope equation for the line that passes through the point (-4,-2) and is parallel to

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3 years ago

Read 2 more answers

The volume of a cylinder of radius 3r and height 6r is given by TT(3r)2(6r). Simplify the expression.

OLga [1]

Answer: $\pi 36r^{2}$

Step-by-step explanation:

ALRIGHT ARE YOU READY FOR EPIC MATH TIME?

because i know i am. so lets get this bread.

WATCH: we have $\pi (3r)2(6r)$

interesting... that first character is called pi. maybe i should have said, "lets get this pi".

so now lets do some algebra. i am going to work from right to left. lets multiply 6r by 2. that gives us 12r. now we have... $\pi (3r)(12r)$

WE ARE MAKING EPIC PROGRESS, AREN'T WE?

lets multiply 12r by 3r. then we have....

$\pi 36r^{2}$

notice how i multiplied 12 by 3 and also r by r (which gives 36 and $r^{2}$ respectively)

so your simplified expression is: $\pi 36r^{2}$

6 0

2 years ago

I really need help with this Triangle problem.

julia-pushkina [17]

Answer:

x = 10

y = 20

Step-by-step explanation:

$\tan \: 30 \degree = \frac{x}{10 \sqrt{3} } \\ \\ \frac{1}{ \sqrt{3} } = \frac{x}{10 \sqrt{3} } \\ \\ \sqrt{3} x = 10 \sqrt{3} \\ \\ x = \frac{10 \sqrt{3} }{ \sqrt{3} } \\ \\ x = 10 \\ \\ \cos 30 \degree = \frac{10 \sqrt{3} }{y} \\ \\ \frac{ \sqrt{3} }{2} = \frac{10 \sqrt{3} }{y} \\ \\ y = 10 \sqrt{3} \times \frac{2}{ \sqrt{3} } \\ \\ y = 10 \times 2 \\ \\ y = 20$

4 0

2 years ago

X+8=-15 help again sorryyy

suter [353]

X by its self is always 1x

1x+8=-15 you have to get rid of 8 by subtracting on both sides

1x=-23 now get rid of 1 by dividing on both sides

x=-23

8 0

2 years ago