(1,500 meters) x (1 sec / 330 meters) = (4 and 18/33) seconds
(4.55 sec, rounded)
At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.
As a result, the manatee now becomes negatively buoyant and must rise to compensate.
<h3>What does it mean when something has neutral buoyancy?</h3>
When something has neutral buoyancy, it is not affected by the weight of anything above or below it.
This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.
Examples of things with neutral buoyancy include air balloons and swimming caps.
To learn more about neutral buoyancy, visit:
brainly.com/question/2170899
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Answer:
A). 11462 Joules
B). 32345.25 Joules
Explanation: The workdone by a variable force undergoing a displacement is in d line of integral.
Find the attached file for the solution.
Answer:
L = 7 [cm]
Explanation:
To solve this problem we must analyze each of the distances mentioned and take into account the number of covers and thicknesses of these.
The worm crosses through the sheets of the first book, this distance can be determined by the following length analysis.
4 = P + 2*C
Where:
P = thicknesses of the pages [cm]
C = thicknesses of each cover [cm]
P = 4 - 2*(0.5)
P = 3 [cm]
The distance crossed was:
L = P + 2C + P "the pages of the first book + 2 covers + the pages of the second book"
L = 3 + (2*0.5) + 3
L = 7 [cm]
