The package should be dropped <u>678 m</u> short of the target.
A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.
The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.
Use the equation,
Write an expression for t, the time taken for the package to fall through y.
Substitute 100 m for y and 9.81m/s² for g.
In the time t the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.
Therefore, the horizontal distance traveled by the package is given by,
If the package is released <u>678m</u> before the target, the package would reach the scientists working in Greenland.
95-2.30+0.1+0.02cm =0.00089186
100m
Answer:
100 degrees is the boiling point on the celsius scale and the freezing point is 0.
Explanation:
Answer:
The Required horizontal force is 230.04N
Explanation:
Since the velocity is constant so acceleration is zero; a=0
Now the horizontal force required to move the pickup is equal to the frictional force.
where:
F_{Hn} is the required Force
u is the friction coefficient
m is the mass
g is gravitational acceleration=9.8m/s^2
Eq (1)
Now, weight increases by 42% and friction coefficient decreases by 19%
New weight=(1.42*m*g) and new friction coefficient=0.81u
Eq (2)
Divide Eq(2) and Eq (1)
The Required horizontal force is 230.04N
Answer:
Speed of the wreck after the collision is 65 km/h
Explanation:
When a car hits truck and sticks together, the collision would be totally inelastic. Since the both the vehicles locked together, they have the same final velocity.
Mass of car 
Mass of truck 
Initial speed of the car 
Initial speed of the truck 
The final velocity of the wreck will be
since final speed are same, 
