The expression for the cost of Taxi B is 0.40<em>x</em> + 2.<em> </em>The expression for the cost of Taxi A is 0.20<em>x</em> + 4. The inequality asks for when the cost of Taxi B will be greater than Taxi A, so you write it as 0.40<em>x </em>+ 2 > 0.20<em>x</em> + 4, or 0.20<em>x</em> + 4 < 0.40<em>x </em>+ 2.
The answer is B) 0.20<em>x</em> + 4 < 0.40<em>x </em>+ 2.
Answer:
a. $11.10
b. 1 689/1110
c. 1.62
d. 15 necklaces
e. $166.50
Step-by-step explanation:
Materials = $2.51
Labor = $4.38
Cost of production = $2.51 + $4.38
= $6.89
Sales price = $17.99
a. Profits = sales price - cost of production
= $17.99 - $6.89
= $11.10
Sally earn $11.10 when she sells a necklace
b. Sales price = $17.99
Profits = 11.10
Fraction of sale price that is profits = $17.99 / $11.10
Multiply both numerator and denominator by 100
= 1799/1110
= 1 689/1110
c. Sales price = $17.99
Profits = 11.10
Decimal of every dollar of the sale price of the necklace that is profit = $17.99 / $11.10
= 1.6207
Approximately 1.62
d. Total selling price of necklace = $269.85
Selling price of each necklace = $17.99
Number of necklace sold = Total selling price of necklace / Selling price of each necklace
= $269.85 / $17.99
= 15 necklaces
(e)
Profits earned per necklace = $11.10
Total profits earned = Profits earned per necklace × Number of necklace sold
= $11.10 × 15
= $166.50
So in this case P = 2000, i = 0.045, and t = 5.
Just substitute, those numbers into the equation, getting you 2000(1+0.045)^5
This then becomes 2000(1.045)^5
Which gets you about 2492.36, or B.
Answer:
1) 3 units
2)4 units
3) 5 units
4)10 units
Step-by-step explanation:
We can use the Distance Formula to find the distance between the two points given to us. The Distance Formula is for points (x1 , y1) & (x2 , y2) is
★ Distance = √[ (x2 - x1)² + (y2 - y1)²]
<u>1) (0,0) & (0,3)</u>
⇒ Distance = √ [ (3-0)²+(0-0)² ]
⇒ Distance = √ [ 3² ]
⇒ Distance = 3 units .
====================================
<u>2</u><u>) (0,0) & (</u><u>4</u><u>,</u><u>0</u><u>)</u>
⇒ Distance = √ [ (4-0)²+(0-0)² ]
⇒ Distance = √ [ 4² ]
⇒ Distance = 4 units .
====================================
<u>3) (0,0) & (4,3)</u>
⇒ Distance = √ [ (3-0)²+(4-0)² ]
⇒ Distance = √ [ 3²+ 4² ]
⇒ Distance = √ 9 + 16
⇒ Distance = √25
⇒ Distance = 5 units .
====================================
<u>4</u><u>) (0,0) & (</u><u>8</u><u>,</u><u>6</u><u>)</u>
⇒ Distance = √ [ (8-0)²+(6-0)² ]
⇒ Distance = √ [ 8²+ 6² ]
⇒ Distance = √ 64 + 36
⇒ Distance = √100
⇒ Distance = 10 units .
4.) 180-25 = 155 a straight line cuts the circle in half (i.e 180 degrees) then subtract out the 25.