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Vilka [71]
3 years ago
15

This is urgent please help me

Mathematics
2 answers:
mars1129 [50]3 years ago
7 0

Answer:

23 mpg

161/7=23

Add in the unit you are measuring by, and you get 23 mpg

abruzzese [7]3 years ago
5 0

Answer:

B: 23

Step-by-step explanation:

Divide 161 by 7 to get 23.

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The answer is 21 or 63/3
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I need help ASAP please
trapecia [35]

Answer:

B

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = \frac{1}{\sqrt{2} } , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{3}{c} = \frac{1}{\sqrt{2} } ( cross- multiply )

c = 3\sqrt{2}

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Circle P and circle Q are similar. What is the scale factor which converts P to Q?
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Answer: C

Step-by-step explanation:

To find the scale factor between circle P and circle Q, divide the diameter of circle Q by the diameter of circle P, 4.5 ft÷1.5 ft = 3. The scale factor between circle P and circle Q is 3.

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A circle with circumference 12 and has an arc with a 48, degrees central angle.What is the length of the arc?
Phantasy [73]

Answer:

0.1754596 ft

Step-by-step explanation:

5 0
4 years ago
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Terry and Callie do word processing. For a certain prospectus Callie can prepare it two hours faster than Terry can. If they wor
Dahasolnce [82]

Time taken by jerry alone is 10.1 hours

Time taken by callie alone is 8.1 hours

<u>Solution:</u>

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is \frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }

If they work together they can do the entire prospectus in five hours

\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}

On cross-multiplication we get,

\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}

\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}

On cross multiplication ,we get

\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}

<em><u>using quadratic formula:-</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

x=\frac{12 \pm \sqrt{144-40}}{2}

\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

3 0
3 years ago
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