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3 years ago

14

After restocking the vending machines, Efrain determined that 2 out of every 5 packages of candy sold were M&M'S®. The vendi

ng machine sold 160 packages of candy last week. How many packages of M&M'S® were sold?

2 answers:

julia-pushkina [17]3 years ago

8 0

Answer:

64

Step-by-step explanation:

Makovka662 [10]3 years ago

7 0

Answer:

64

Step-by-step explanation:

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PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM

Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y=1, z=0

6 0

3 years ago

The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

hoa [83]

Answer:

8 packs of bottled water and 14 packs of candy bars

Step-by-step explanation:

Provided,

Each pack of water bottles = 35 bottles

Each pack of candy = 20 candy

Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,

Purchase quantity of candy packs shall be more than the pack of water bottles.

Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.

In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.

Accordingly

Option 3

8 packs of water bottle = $8 \times 35 = 280 \ water\ bottles$

14 packs of candy = $14 \times 20 = 280 \ candies$

Since the quantities of water bottles and candies are same this is an opt answer.

6 0

4 years ago

Read 2 more answers

Which ordered pair is in the solution set of the system of linear inequalities graphed below?

motikmotik

Answer:

Graphed?

Step-by-step explanation:

5 0

3 years ago

What is the percent change of 6 <br> to 36

Kaylis [27]

There is a 483% Change

4 0

3 years ago

Which best describes how to solve the equation for x.

prohojiy [21]

Answer:

B. multiply both sides by c.

Step-by-step explanation:

To solve the equation for x, you have to isolate the x variable on one side of the equation. To do this, do the opposite of any operation applied to x to remove other variables from the x's side of the equation:

x/c = d

multiply both sides of the equation by c to isolate x:

(x/c) * c = d * c

x = dc

Now x can be solved for.

Hope this helps :)

7 0

3 years ago